public V remove(Object key) { Entry<K,V> e = removeEntryForKey(key); return (e == null ? null : e.value); } final Entry<K,V> removeEntryForKey(Object key) { int hash = (key == null) ? 0 : hash(key); int i = indexFor(hash, table.length); Entry<K,V> prev = table...
void addEntry(int hash, K key, V value, int bucketIndex) { // 调用父类的addEntry,增加一个Entry到HashMap中 super.addEntry(hash, key, value, bucketIndex); // removeEldestEntry方法默认返回false,不用考虑 Entry<K,V> eldest = header.after; if (removeEldestEntry(eldest)) { removeEntryForKey...
voidaddEntry(inthash, K key, Vvalue,intbucketIndex){// 调用父类的addEntry,增加一个Entry到HashMap中super.addEntry(hash, key,value, bucketIndex);// removeEldestEntry方法默认返回false,不用考虑Entry<K,V> eldest = header.after;if(removeEldestEntry(eldest)) { removeEntryForKey(eldest.key); } }...
LinkedHashMap 继承了 HashMap,基本操作(add, contains and remove)可以认为是O(1),因需要维护双链表,性能可能会略低于 HashMap,但是有一个例外:LinkedHashMap 的迭代只与实际大小有关(毕竟可以依靠双链表进行迭代),而 HashMap 的迭代则与容量有关,性能会相对低于 LinkedHashMap。 同样不适合多线程操作,需要额外...
Node(Node<E> prev, E element, Node<E> next) { this.item = element; this.next =...
If the map is modified while an iteration over the set is in progress (except through the iterator's own remove operation, or through the setValue operation on a map entry returned by the iterator) the results of the iteration are undefined. The set supports element removal, which removes ...
if(removeEldestEntry(eldest)) {removeEntryForKey(eldest.key); }else{//扩容到原来的2倍if(size>= threshold)resize(2* table.length); } }voidcreateEntry(inthash, Kkey, V value,intbucketIndex) {// 向哈希表中插入Entry,这点与HashMap中相同//创建新的Entry并将其链入到数组对应桶的链表的头结点...
removeEntryForKey(eldest.key); } else { //扩容到原来的2倍 if (size >= threshold) resize(2 * table.length); } } void createEntry(int hash, K key, V value, int bucketIndex) { // 向哈希表中插入Entry,这点与HashMap中相同 //创建新的Entry并将其链入到数组对应桶的链表的头结点处, ...
This implementation merely returns false (so that this map acts like a normal map - the eldest element is never removed). Parameters: eldest - The least recently inserted entry in the map, or if this is an access-ordered map, the least recently accessed entry. Th...
If there was an element, then element's can be obtained by iterator's Value() function. Depending on the ordering type, it's position can be obtained by iterator's Index() or Key() functions. Some containers even provide reversible iterators, essentially the same, but provide another extra...