LinkedHashMap没有提供remove方法,所以调用的是HashMap的remove方法,实现如下: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 public V remove(Object key) { Entry<K,V> e = removeEntryForKey(key); return (e == null ? null : e.value); } final Entry<K,V> removeEntryForKey(Object key)...
publicVput(K key, Vvalue){// 对key为null的处理if(key ==null)returnputForNullKey(value);// 计算hashinthash = hash(key);// 得到在table中的indexinti = indexFor(hash, table.length);// 遍历table[index],是否key已经存在,存在则替换,并返回旧值for(Entry<K,V> e = table[i]; e !=null...
LinkedHashMap 继承了 HashMap,基本操作(add, contains and remove)可以认为是O(1),因需要维护双链表,性能可能会略低于 HashMap,但是有一个例外:LinkedHashMap 的迭代只与实际大小有关(毕竟可以依靠双链表进行迭代),而 HashMap 的迭代则与容量有关,性能会相对低于 LinkedHashMap。 同样不适合多线程操作,需要额外...
void addEntry(int hash, K key, V value, int bucketIndex) { // 调用父类的addEntry,增加一个Entry到HashMap中 super.addEntry(hash, key, value, bucketIndex); // removeEldestEntry方法默认返回false,不用考虑 Entry<K,V> eldest = header.after; if (removeEldestEntry(eldest)) { removeEntryForKey...
if(removeEldestEntry(eldest)) {removeEntryForKey(eldest.key); }else{//扩容到原来的2倍if(size>= threshold)resize(2* table.length); } }voidcreateEntry(inthash, Kkey, V value,intbucketIndex) {// 向哈希表中插入Entry,这点与HashMap中相同//创建新的Entry并将其链入到数组对应桶的链表的头结点...
(except through the iterator's ownremoveoperation, or through thesetValueoperation on a map entry returned by the iterator) the results of the iteration are undefined. The set supports element removal, which removes the corresponding mapping from the map, via theIterator.remove,Set.remove,...
null : e.value; } final Node<K,V> removeNode(int hash, Object key, Object value, boo...
* Returns <tt>true</tt> if this map should remove its eldest entry. * This method is invoked by <tt>put</tt> and <tt>putAll</tt> after * inserting a new entry into the map. It provides the implementor * with the opportunity to remove the eldest entry each time a new one ...
removeEntryForKey(eldest.key); } else { //扩容到原来的2倍 if (size >= threshold) resize(2 * table.length); } } void createEntry(int hash, K key, V value, int bucketIndex) { // 向哈希表中插入Entry,这点与HashMap中相同 //创建新的Entry并将其链入到数组对应桶的链表的头结点处, ...
Simply put, any access operation on the map results in an order such that the element that was accessed would appear last if an iteration were to be carried out right away. After the above examples, it should be obvious that aputAlloperation generates one entry access for each of the mappi...