class Solution: def longestWord(self, words): """ :type words: List[str] :rtype: str """ # 答案来自https://leetcode.com/…阅读全文 赞同 添加评论 分享收藏 717. 1-bit and 2-bit Characters class Solution: def isOneBitCharacter(self, bits): """ :type bits: ...
# Definition for singly-linked list.# class ListNode(object):# def __init__(self, val=0, next=None):# self.val = val# self.next = nextclassSolution(object):defaddTwoNumbers(self, l1, l2):""" :type l1: ListNode :type l2: ListNode :rtype: ListNode """temp = p = ListNode(None...
Python3版本 classSolution:defisValid(self, s:str) ->bool: stack = []# 创建一个栈用于存储左括号字符brackets = {'(':')','[':']','{':'}'}forcharins:ifcharinbrackets.keys():# 如果是左括号字符,将其压入栈中stack.append(char)elifcharinbrackets.values():# 如果是右括号字符ifnotstack:...
由于题目中已经标明就是两个整数相加等于target值,那我们只需要通过target-nums[i]确定待查找的值,然后去Map中查找即可,如下所示: 步骤三:在这个例子中,就从Map中匹配到了key=7,value=[1,3]的这种情况。那么由于i=1,所以我们匹配的另一个整数值就是3了,所以返回的匹配结果就是result=[1, 3] 【总结】 首...
Python实现：```python class Solution:def repeatedStringMatch(self, a: str, b: str) -> int:max\_count = len(b) // len(a) + 2 for i in range(1, max\_count + 1):repeated\_a = a i if b in repeated\_a:return i return -1 ```注意，由于Python的成员关系运算符in会检查子串...
485. 最大连续 1 的个数(Easy) 方法一: 将数组尾部插入一个0,每碰见一个0,就统计两个0之间有多少个1 class Solution: def findMaxConsecutiveOnes(self, nums: List[int]) -> int: pre_zero_index = -1 res = 0 nums.append(0) for i, num in enumerate(nums): ...
classSolution{privateint[]memo;publicintnumWays(int n){memo=newint[n+1];Arrays.fill(memo,-1);returnjump(n);}privateintjump(int n){if(memo[n]!=-1){returnmemo[n];}if(n==1||n==0){return1;}memo[n]=(jump(n-1)+jump(n-2))%1000000007;returnmemo[n];}} ...
Python3版本 class Solution: def isValid(self, s: str) -> bool: stack = [] # 创建一个栈用于存储左括号字符 brackets = {'(': ')', '[': ']', '{': '}'} for char in s: if char in brackets.keys(): # 如果是左括号字符,将其压入栈中 stack.append(char) elif char in brackets...
Python3版本 class Solution: def isSymmetric(self, root: TreeNode) -> bool: if root is None: return True # 如果根节点为空,返回True,空树被认为是对称的 return self.isMirror(root.left, root.right) def isMirror(self, left: TreeNode, right: TreeNode) -> bool: ...
1 Suffix Array Python 2 Longest Common Prefix Python LeetCode Algorithm Problems 1100-1200 #TitleSolutionDifficulty 1296 Divide Array in Sets of K Consecutive Numbers Python Medium 1295 Find Numbers with Even Number of Digits Python Easy 1291 Sequential Digits Python Medium 1290 Convert Binary Number...