来源:https://leetcode.com/problems/nim-game/ solution classSolution(object):defcanWinNim(self, n):""" :type n: int :rtype: bool """return(n %4!=0)
0:aliveBuilds.top().first;if(result.empty()||(result.back().second!=cur_H))result.push_back(make_pair(cur_X,cur_H));}returnresult;}}; Solution2. Python3 Success Details Runtime: 64 ms, faster than 98.97% of Python3 online submissions for The Skyline Problem. Memory Usage: 16.8 M...
#Definition for a binary tree node.#class TreeNode(object):#def __init__(self, x):#self.val = x#self.left = None#self.right = NoneclassSolution(object):defmaxDepth(self, root):""":type root: TreeNode :rtype: int"""returnself.search(root, 0)defsearch(self, node, i):ifnodeis...
class Solution(object): def twoSum(self, nums, target): for i in xrange(len(nums) - 1): for j in xrange(i+1, len(nums)): if nums[i] + nums[j] == target: return [i, j] 思路2:利用python里面的字典记录下每个元素出现的位置,遍历一次即可。算法复杂度O(n) class Solution(object):...
对应的 Java 仓库的地址,传送门:https://github.com/liweiwei1419/LeetCode-Solution-Java 说明:现在刷题,尤其是写题解,绝大多数问题都会写两个语言的代码,Java 是我的母语,Python 是我的新欢。 发布在 LeetCode 中文版上的题解配图使用的 PPT,传送门:https://github.com/liweiwei1419/LeetCode-Solution-PPT...
#TitleSolutionTimeSpaceDifficultyTagNote 2007 Find Original Array From Doubled Array C++ Python O(n + klogk) O(k) Medium variant of Array of Doubled Pairs 2011 Final Value of Variable After Performing Operations C++ Python O(n) O(1) Easy 2012 Sum of Beauty in the Array C++ Python O...
Title: LeetCode Problem 772. Basic Calculator III 简要分析及Python代码 Date: 2018-01-24 Category: Programming Tags: LeetCode, Python, Programming, Solution, Hard, Algorithm Slug: leetcode-765 Author: ouankou LeetCode 第772题 Basic Calculator III 简要分析及Python代码 ...
return [i,j] 但是报错了(还是本人基本语法掌握不好) 经查阅后 错误消息"TypeError: ‘int’ object is notiterable"通常在Python中出现,当您尝试像遍历(循环)可迭代对象一样遍历整数(int)值时,比如列表、元组或字符串等时会出现此错误。在Python中,您只能遍历支持迭代的对象,如序列和集合。总的来看:列表、字典...
Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. 题意分析: 给定一个二叉树,判断其是否是平衡二叉树 ...
Solution 2: Useset defnumJewelsInStones(self,J,S):f=set(J)returnsum([sinfforsinS]) Time complexity:O(|J|*|S|) The operationa in bhas different time complexity inlistandset, see here:https://wiki.python.org/moin/TimeComplexity ...