来源:https://leetcode.com/problems/nim-game/ solution classSolution(object):defcanWinNim(self, n):""" :type n: int :rtype: bool """return(n %4!=0)
#Definition for a binary tree node.#class TreeNode(object):#def __init__(self, x):#self.val = x#self.left = None#self.right = NoneclassSolution(object):defmaxDepth(self, root):""":type root: TreeNode :rtype: int"""returnself.search(root, 0)defsearch(self, node, i):ifnodeis...
对应的 Java 仓库的地址,传送门:https://github.com/liweiwei1419/LeetCode-Solution-Java 说明:现在刷题,尤其是写题解,绝大多数问题都会写两个语言的代码,Java 是我的母语,Python 是我的新欢。 发布在 LeetCode 中文版上的题解配图使用的 PPT,传送门:https://github.com/liweiwei1419/LeetCode-Solution-PPT...
代码实现: classSolution:deftwoSum(self,nums:List[int],target:int)->List[int]:foriinrange(len(nums)):forjinrange(i+1,len(nums)):ifnums[i]+nums[j]==target:return[i,j] 解题思路:嵌套遍历从数组中取出两个数相加,用嵌套的for循环,判断相加的结果是否满足要求,如果满足则用列表返回两个数据的索...
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739.每日温度 给定一个整数数组temperatures，表示每天的温度，返回一个数组answer，其中answer[i]是指对于...
剑指offer-python版(下) 31.从1到n的整数中1出现的个数 比如,1-13中,1出现6次,分别是1,10,11,12,13。classSolution:defNumberOf1Between1AndN_Solution(self,n):count=0foriinrange(1,n+1… 阅读全文 赞同 144 17 条评论
Solution 2: Useset defnumJewelsInStones(self,J,S):f=set(J)returnsum([sinfforsinS]) Time complexity:O(|J|*|S|) The operationa in bhas different time complexity inlistandset, see here:https://wiki.python.org/moin/TimeComplexity ...
#TitleSolutionTimeSpaceDifficultyTagNote 2151 Maximum Good People Based on Statements C++ Python O(n^2 * 2^n) O(1) Hard Bitmasks, Brute Force 2212 Maximum Points in an Archery Competition C++ Python O(n * 2^n) O(n) Medium Bitmasks, Brute Force 2220 Minimum Bit Flips to Convert Number...
Leetcode Palindrome Number Python Solution 判断回文数的python解法 二话不说,直接上代码: 1classSolution(object):2defisPalindrome(self, x):3"""4:type x: int5:rtype: bool6"""7x2 = str(x)8ifx2 == x2[::-1]:9returnTrue10else:11returnFalse...