public class Solution { public string ReverseOnlyLetters(string s) { int n = s.Length; char[] arr = s.ToCharArray(); int left = 0, right = n - 1; while (true) { while (left < right && !char.IsLetter(s[left])) { // 判断左边是否扫描到字母 left++; } while (right > ...
此解法的时间复杂度是O(N),空间复杂度是O(N)。 publicStringreverseOnlyLetters2(String S){intj=S.length()-1, n = S.length();StringBuildersb=newStringBuilder();for(inti=0; i<n; i++) {if(Character.isLetter(S.charAt(i))) {while(j>=0&& !Character.isLetter(S.charAt(j))) { j--;...
1、题目描述 2、题目描述 利用栈实现逆序。 3、代码 1stringreverseOnlyLetters(stringS) {2if(S.size() ==0|| S.size() ==1)3returnS;45stack<string>st;6for(string::iterator it = S.begin(); it != S.end(); it++) {7if( isalpha(*it) ){8stringsub = S.substr(it-S.begin(),1);...
两个指针向中间移动,当左右指针相遇时停止,每个指针在遇到非字母时直接跳过,当左右指针都指向字母时交换,不断重复直到指针相遇。 classReverseOnlyLetters{funreverseOnlyLetters(S:String):String{valresult=CharArray(S.length)varstart=0varend=S.lastIndexwhile(start<=end){if(!S[start].isLetter()){result[st...
所有英文字母(小写或大写)位置反转。 返回反转后的s* 。* image.png 我的题解 确实是简单题,栈思想 classSolution:defreverseOnlyLetters(self,s:str)->str:arr=[]forn,cinenumerate(s):ifc.isalpha():arr.append(c)ls=list(s)forn,cinenumerate(s):ifc.isalpha():ls[n]=arr.pop()return''.join(ls...
void func(char* tmp, int len) { int left = 0, right = len - 1; while (left < right) { char t = tmp[left]; tmp[left] = tmp[right]; tmp[right] = t; left++; right--; } } char* reverseOnlyLetters(char* s) { int len = strlen(s), cur = 0; char tmp[len]; for (...
953 reverse-only-letters 📝 Easy 954 maximum-sum-circular-subarray 📝 Medium 955 complete-binary-tree-inserter 📝 Medium 956 number-of-music-playlists 📝 Hard 957 minimum-add-to-make-parentheses-valid 📝 Medium 958 sort-array-by-parity-ii 📝 Easy 959 3sum-with-multiplicity 📝 Medium...
(*)https://leetcode.com/problems/reverse-string/ https://leetcode.com/problems/reverse-vowels-of-a-string/ https://leetcode.com/problems/valid-palindrome-ii/ https://leetcode.com/problems/reverse-only-letters/ https://leetcode.com/problems/remove-element/ ...
917 Reverse Only Letters 56.30% Easy 916 Word Subsets 45.90% Medium 915 Partition Array into Disjoint Intervals 43.90% Medium 914 X of a Kind in a Deck of Cards 34.00% Easy 913 Cat and Mouse 29.90% Hard 912 Sort an Array 62.90% Medium 911 Online Election 48.30% Medium 910 Smallest Range...
You are given a stringsthat consists of lower case English letters and brackets. Reverse the strings in each pair of matching parentheses, starting from the innermost one. Your result should not contain any brackets. Example 1: Input: s = "(abcd)" ...