5 public: 6 int reverse(int x) { 7 long long res = 0; 8 bool isPositive = true; 9 if (x < 0) { 10 isPositive = false; 11 x *= -1; 12 } 13 while (x > 0) { 14 res = res * 10 + x % 10; 15 x /= 10; 16 } 17 if (res > INT_MAX) return 0; 18 if (is...
Reverse Level Order Traversal (easy) Zigzag Traversal (medium) Level Averages in a Binary Tree (easy) Minimum Depth of a Binary Tree (easy) Level Order Successor (easy) Connect Level Order Siblings (medium) 8. Pattern: Tree Depth First Search,树上的DFS 树形DFS基于深搜(Depth First Search (...
Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases?For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.我比较认可的做法:...
* @链接:https://leetcode-cn.com/problems/palindrome-number/solution/9-hui-wen-shu-jiang-ti-jie-fu-zhi-dao-liu-lan-qi-k/ */varisPalindrome=function(x){if(x<0||(x%10==0&&x!=0)){returnfalse;}varreverseNumber=0;while(x>reverseNumber){reverseNumber=reverseNumber*10+x%10;x=parseInt...
【输入】number = "123 4-5678" 【输出】"123-456-78" 2.4> 示例 4: 【输入】number = "12" 【输出】"12" 2.5> 示例 5: 【输入】number = "--17-5 229 35-39475 " 【输出】"175-229-353-94-75" 提示: •2<= number.length <=100 ...
Givenanintegerarraynums,returnthenumberofreversepairsinthearray. Areversepairisapair(i,j)where0<=i<j<nums.lengthandnums[i]>2*nums[j]. 给定一个数组 nums ,如果 i < j 且 nums[i] > 2*nums[j] 我们就将 (i, j) 称作一个重要翻转对。 你需要返回给定数组中的重要翻转对的数量。 示例 示例...
* ListNode(int x, ListNode *next) : val(x), next(next) {} * }; */ class Solution { public: ListNode* reverseList(ListNode* head) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2Case 3 head = [1,2,3,4,5] 1 2 3 [1,2,3,4,5] [1,2] [] Source ...
151. Reverse Words in a String Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". 题目大意: 输入一个字符串,将单词序列反转。 思路1: 采用一个vector,来存放中间结果 ...
leetcode 151 - reverse-words-in-a-string: 先把string按照空格分成词语,然后把这些词语从后往前组合 滑动窗口的方法,通常适用与寻找子串或者子数组的情况,分别设置左右指针,适时的移动左右指针,保证滑动窗口中的元素满足某个条件 Examples: leetcode 209. Minimum Size Subarray Sum#49 ...
给定一个字符串s,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序。 示例1: 输入:s = "Let's take LeetCode contest"输出:"s'teL ekat edoCteeL tsetnoc" 示例2: 输入:s = "Mr Ding"输出:"rM gniD" 提示: 1 <= s.length <= 5 * 104 ...