https://leetcode.com/problems/reverse-integer/ understanding: 最intuitive的办法就是直接把integer化成string,然后变成list。这里如果化成string,会有溢出的问题,比如integer是1534236469,这个数字反过来就是个很大的数,溢出了,必须返回0. 如果是直接用int计算的,那就会自动溢出得到正确结果。这里如果变成list,则效率底下。
self.reverseStrs(l,0, len(l)-1) #2.翻转字符 # ['y','a','d','o','t',' ','g','n','i','n','i','a','r',' ','s','i',' ','t','i'] self.reverseEachWord(l) #3.翻转每个单词 # ['t','o','d','a','y',' ','r','a','i','n','i','n','g',...
LeetCode: 92. Reverse Linked List II 题目描述 Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5-...
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space. For example, Given s = "the sky is blue", return "blue ...
思路 Step1 : reverse the whole char of string word by word. the sky is blue -> eulb si yks eht Step2: reverse the characters word by word, use two pointer, left is the start of the word and right keep track of the word which is not a space, when it reaches a space, then reve...
比较基础的一个题,拿到这个题,我的第一想法是利用vector来存每一个子串,然后在输出,这是一个比较简单的思路,此外,还有第二个思路,就是对所有的字符反转,然后在针对每一个子串反转,但是这个时候要注意它的要求,保证每个子串中只有一个空格。我是按照第一种思路,代码如下: ...
A set of practice note, solution, complexity analysis and test bench to leetcode problem set - leetcode/add Reverse Linked List II.drawio at b58bcceb0ea27d0756ad72fb6a64b3b547fae221 · brianchiang-tw/leetcode
给你一个 32 位的有符号整数x,返回将x中的数字部分反转后的结果。 如果反转后整数超过 32 位的有符号整数的范围[−231, 231− 1],就返回 0。 假设环境不允许存储 64 位整数(有符号或无符号)。 示例1: 输入:x = 123输出:321 示例2: 输入:x = -123输出:-321 ...
151. Reverse Words in a String Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". 题目大意: 输入一个字符串,将单词序列反转。 思路1: 采用一个vector,来存放中间结果 ...
Problem Write a function that takes a string as input and reverse only the vowels of a string. Example 1: Givens = "hello", return "holle". Example 2: Givens = "leetcode", return "leotcede". Note 第一种解法:将字符串转化为字符数组,用一头一尾两个指针向中间夹逼,遇到两个元音字母就进行...