int rangeSumBST(TreeNode*root,intL,intR) { if (!root) return 0; if (root->val<L) return rangeSumBST(root->right,L,R); if (root->val>R) return rangeSumBST(root->left,L,R); return root->val + rangeSumBST(root->left,L,R) + rangeSumBST(root->right,L,R); } }; Github ...
classSolution{ publicintrangeSumBST(TreeNode root,intlow,inthigh){ if(root ==null) { return0; } if(root.val > high) { returnrangeSumBST(root.left, low, high); } if(root.val < low) { returnrangeSumBST(root.right, low, high); } returnroot.val + rangeSumBST(root.left, low, h...
* type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */ func rangeSumBST(root *TreeNode, low int, high int) int { // 如果 root 子树为空,则直接返回 0 if root == nil { return 0 } // ans 维护 root 子树中,所有结点值在 [low, high] 内结点值之和 ans...
题目地址:https://leetcode.com/contest/weekly-contest-110/problems/range-sum-of-bst/ 题目描述 Given therootnode of a binary search tree, return the sum of values of all nodes with value betweenLandR(inclusive). The binary search tree is guaranteed to have unique values. Example 1: Input: ...
https://leetcode.com/problems/range-sum-of-bst/ 题目: Given therootnode of a binary search tree, return the sum of values of all nodes with value betweenLandR(inclusive). The binary search tree is guaranteed to have unique values.
{bst.rangeSum(-1,id)} + ${bst.rangeSum(preId, n - 1)}") } // 单点更新 bst.dec(id) preId = id } return ret } // 树状数组 private class BST(private val n: Int) { // base 1 private val data = IntArray(n + 1) init { // O(nlgn) 建树 // for (i in 0 .. n)...
Range Sum Query – Mutable 【题目】Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: 代码语言:javascript ...
rightclassSolution:defrangeSumBST(self,root:Optional[TreeNode],low:int,high:int)->int:defrangeSum(t):_sum=0ifnott:return_sumelift.val<low:_sum+=rangeSum(t.right)elift.val>high:_sum+=rangeSum(t.left)else:_sum+=t.val+rangeSum(t.left)+rangeSum(t.right)return_sumreturnrangeSum(root...
root.right=self.sortedArrayToBST(num[mid+1:])returnroot Balanced Binary Tree 题目:Balanced Binary Tree Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every nod...
0938 Range Sum of BST 78.80% Easy 0939 Minimum Area Rectangle 50.50% Medium 0940 Distinct Subsequences II 39.80% Hard 0941 Valid Mountain Array 35.50% Easy 0942 DI String Match Go 70.00% Easy 0943 Find the Shortest Superstring 38.30% Hard 0944 Delete Columns to Make Sorted 69.40% Ea...