}intquerySumTree(SumTreeNode* p,inti,intj){if(p->range.first == i && p->range.second == j)returnp->sum;//叶节点if(p->left->range.second >= j){//仅在左子树的范围内returnquerySumTree(p->left, i, j); }elseif(p->right->range.first <= i){//仅在右子树的范围内returnqueryS...
Can you solve this real interview question? Range Sum Query - Mutable - Given an integer array nums, handle multiple queries of the following types: 1. Update the value of an element in nums. 2. Calculate the sum of the elements of nums between indice
/*class NumArray { public: NumArray(vector<int> nums) { myNums.swap(nums); } int sumRange(int i, int j) { int sum = 0; for(int q = i; q <= j; ++q){ sum += myNums[q]; } return sum; } private: vector<int> myNums; };*/ class NumArray { public: NumArray(vector...
sumRange(0, 2) -> 9 update(1, 2) sumRange(0, 2) -> 8 1. 2. 3. 4. 5. Note: The array is only modifiable by the update function. You may assume the number of calls to update and sumRange function is distributed evenly. 解题思...
https://leetcode.com/problems/range-sum-query-immutable/题目: Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. Example: Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 ...
LeetCode 307. Range Sum Query - Mutable 简介:update(i, val) 函数可以通过将下标为 i 的数值更新为 val,从而对数列进行修改。 Description Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive....
{} if len(nums) <= 1 { nn = nums } else { nn = append(nn, nums[0]) for i := 1; i < len(nums); i++ { nn = append(nn, nums[i]+nn[i-1]) } } return NumArray{ nums: nn, } } func (this *NumArray) SumRange(i int, j int) int { if i == 0 { return this...
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sumRange(0, 2) -> 9 update(1, 2) sumRange(0, 2) -> 8 备注: 该数组只能被update函数修改。 你可以假设update和sumRange函数的调用是均匀分布的。 原文 Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. ...
Range Sum Query – Mutable 【题目】Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: 代码语言:javascript ...