我们也可以不使用HashMap,直接使用数组,另外,题目还说了此二叉树是个BST,那么它的中序遍历的节点值是有序的,那么我们可以直接使用双指针而不必排序,对所有的节点值直接判断。 /***Definitionfora binary tree node.*publicclassTreeNode {*intval;*TreeNode left;*TreeNode right;*TreeNode(int x) {val=x; ...
链接:https://leetcode-cn.com/problems/two-sum-bsts 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 这道题我给出两种思路。一是利用hashset,二是利用BST的中序遍历。 hashset 的做法是,我们为这两棵树各自创建一个 hashset 来记录这两棵树里面的节点值。记录好以后,我们遍历其中一...
leetcode No653:https://leetcode.com/problems/two-sum-iv-input-is-a-bst/ Given a Binary Search Treeanda target number,returntrueifthere exist two elementsinthe BST such that their sumisequaltothe given target.Example1:Input:5/\36/\ \247Target=9Output:True Example2:Input:5/\36/\ \247...
今天介绍的是LeetCode算法题中Easy级别的第148题(顺位题号是653)。给定二进制搜索树和目标数,如果BST中存在两个元素,使得它们的总和等于给定目标,则返回true。例如: 5 / \ 3 6 / \ \ 2 4 7 目标值:9 输出:true 5 / \ 3 6 / \ \ 2 4 7 ...
Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: True Example 2: Input: 5 / \ 3 6 / \ \ 2 4 7 Targe...
Can you solve this real interview question? Two Sum IV - Input is a BST - Given the root of a binary search tree and an integer k, return true if there exist two elements in the BST such that their sum is equal to k, or false otherwise. Example 1:
:pencil: Python / C++ 11 Solutions of All LeetCode Questions - LeetCode/two-sum-iv-input-is-a-bst.cpp at master · evilchaos/LeetCode
653. Two Sum IV - Input is a BST ru代码人生 use std::borrow::Borrow; use std::cell::RefCell; use std::collections::HashMap; use std::ops::Index; use std::rc::Rc;/**653. Two Sum IV - Input is a BSThttps://leetcode.com/problems/two-sum-iv-input-is-a-bst/Given the root...
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https://leetcode.com/problems/two-sum-iv-input-is-a-bst/ https://leetcode.com/problems/sum-of-square-numbers/ https://leetcode.com/problems/boats-to-save-people/ https://leetcode.com/problems/minimize-maximum-pair-sum-in-array/