链接:https://leetcode-cn.com/problems/two-sum-bsts 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 这道题我给出两种思路。一是利用hashset,二是利用BST的中序遍历。 hashset 的做法是,我们为这两棵树各自创建一个 hashset 来记录这两棵树里面的节点值。记录好以后,我们遍历其中一个 has
1. Two SumEasy Topics Companies Hint Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target. You may assume that each input would have exactly one solution, and you may not use the same element twice. You can return ...
Can you solve this real interview question? Two Sum IV - Input is a BST - Given the root of a binary search tree and an integer k, return true if there exist two elements in the BST such that their sum is equal to k, or false otherwise. Example 1: [
167. Two Sum II - Input array is sorted Given an array of integers that is alreadysorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where inde...
leetcode 653 Two Sum IV - Input is a BST 详细解答 解法1 因为这个是二叉搜索树,可以想到先将二叉树进行中序遍历得到一个有序数组,然后然后双指针 (leetcode 167)来求解。 代码如下: 时间复杂度:O(N),空间复杂度:O(N) 解法2 这里借用set进行查询。用层序遍历依次查询。 时间复杂度:O(N), 空间复杂...
题目描述 给定一个BST和一个目标结果,如果BST中存在两个元素且它们的和等于给定的目标结果,则返回true。 思路 参考自:https://leetcode-cn.com/problems/two-sum-iv-input-is-a-bst/solution/liang-shu-zhi-he-iv-by-leetcode/ 使用中序遍历得到有序数组之后,再利用双指针对数组进行查找。 应该 ...
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1. Two Sum刷题笔记 问题描述第一版代码,复杂度为n平方 class Solution: def twoSum(self, nums: List[int], target: int) -> List[int]: for i in range(len(nums)-1): summand = target-nums[i] for j in range(i+1,len(nums)):...
653. Two Sum IV - Input is a BST 题目: Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \...