The n-queens puzzle is the problem of placing n queens on an n×n chessboard such that no two queens attack each other. Given an integer n, return all distinct solutions to the n-queens puzzle. Each solution contains a distinct board configuration of the n-queens' placement, where 'Q' ...
时间复杂度O(n^2),空间O(1) 4. Manacher算法,时间复杂度O(n), 空间复杂度O(n)。 具体参考如下链接: http://articles.leetcode.com/2011/11/longest-palindromic-substring-part-ii.html classSolution {public:stringlongestPalindrome(strings) {intn =2*s.length() +3;charcstr[n]; cstr[0] ='\1'...
[3].https://leetcode-cn.com/problems/shu-zu-zhong-de-ni-xu-dui-lcof/solution/jian-zhi-offer-51-shu-zu-zhong-de-ni-xu-pvn2h/
Problem 1: Leetcode 225 请你仅使用两个队列实现一个后入先出(LIFO)的栈,并支持普通栈的全部四种操作(push、top、pop 和 empty)。 实现MyStack 类: void push(int x) 将元素 x 压入栈顶。 int pop() 移除并返回栈顶元素。 int top() 返回栈顶元素。 boolean empty() 如果栈是空的,返回 true ;否...
121. 买卖股票的最佳时机 - 给定一个数组 prices ,它的第 i 个元素 prices[i] 表示一支给定股票第 i 天的价格。 你只能选择 某一天 买入这只股票,并选择在 未来的某一个不同的日子 卖出该股票。设计一个算法来计算你所能获取的最大利润。 返回你可以从这笔交易中获取的
The n-queens puzzle is the problem of placing n queens on an n×n chessboard such that no two queens attack each other. Given an integer n, return all distinct solutions to the n-queens puzzle. Each solution contains a distinct board configuration of the n-queens' placement, where 'Q' ...
七周掌握高频算法考点,学-练-测全方位夯实,剑指大厂 Offer! 猜你喜欢 两数之和 更多 两数之和 📺 视频题解 📖 文字题解 方法一:暴力枚举 思路及算法 最容易想到的方法是枚举数组中的每一个数 x,寻找数组中是否存在 target - x。 当我们使用遍历整个数组的方式寻找 target - x 时,需要注意到每一个位...
51. N-Queens Then-queens puzzle is the problem of placingnqueens on ann×nchessboard such that no two queens attack each other. Given an integern, return all distinct solutions to then-queens puzzle. Each solution contains a distinct board configuration of then-queens' placement, where'Q'and...
from collectionsimportdefaultdictclassSolution:defmaxPoints(self,points):""":type points:List[Point]:rtype:int""" slopes,result=defaultdict(int),0fori,point1inenumerate(points):slopes.clear()duplicate=1for_,point2inenumerate(points[i+1:]):ifpoint1.x==point2.x and point1.y==point2.y:dup...
class Solution { private int[][] arr; private List<List<String>> ans = new ArrayList<>(); private int n; private int countQ = 0; public List<List<String>> solveNQueens(int n) { this.n = n; arr = new int[n + 2][n + 2]; for (int i = 0; i < n; i++) { dg(1,...