Problem 1: Leetcode 225 请你仅使用两个队列实现一个后入先出(LIFO)的栈,并支持普通栈的全部四种操作(push、top、pop 和 empty)。 实现MyStack 类: void push(int x) 将元素 x 压入栈顶。 int pop() 移除并返回栈顶元素。 int top() 返回栈顶元素。 boolean empty() 如果栈是
直接套状态转移方程,根据 base case,可以做一些化简: dp[i][1][0]=max(dp[i-1][1][0],dp[i-1][1][1]+prices[i])dp[i][1][1]=max(dp[i-1][1][1],dp[i-1][0][0]-prices[i])=max(dp[i-1][1][1],-prices[i])解释:k=0的 basecase,所以 dp[i-1][0][0]=0。现在发现...
Baozi Leetcode solution 6: ZigZag Conversion Problem Statement The string"PAYPALISHIRING"is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility) P A H N A P L S I I G Y I R And then read ...
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leetcode problem 6: zigzag word class Solution { public: string convert(string s, int numRows) { if (numRows == 1){ return s; } string out; for (int i = 0; i < numRows; ++i){ int j = 0; while (true){ int pos = -1; if (j % 2 == 0){ pos = j * (numRows -...
from collectionsimportdefaultdictclassSolution:defmaxPoints(self,points):""":type points:List[Point]:rtype:int""" slopes,result=defaultdict(int),0fori,point1inenumerate(points):slopes.clear()duplicate=1for_,point2inenumerate(points[i+1:]):ifpoint1.x==point2.x and point1.y==point2.y:dup...
solution feat: add solutions to lc problem: No.2434 (#4465) Jun 6, 2025 .clang-format style: update format options Sep 6, 2022 .editorconfig chore: add configuration file .editorconfig (#3336) Jul 31, 2024 .gitignore chore: update .gitignore Apr 26, 2025 ...
A collection of Python codes for Leetcode Problem of the Day leetcode leetcode-solutions leetcode-practice leetcode-python leetcode-python3 leetcode-solution leetcode-programming-challenges leetcode-solutions-python problem-of-the-day problem-of-the-day-solutions leetcode-potd Updated Dec 23, ...
第1行,间隔为8 = 2⋅(5−1)2⋅(5−1)2 \cdot (5-1) 第2行,间隔为6/2交替 第3行,间隔为4/4 第4行,间隔为2/6交替 第5行,间隔为8 如果觉得不够直观,可以看看另一个例子<”THISPROBLEMISAWESOME”, 4>(位置重排): 根据重排的图,有一种较直观的思路: 用一个字符串str来存储每一行中字...
function testWeightBagProblem(wight, value, size) { const len = wight.length, dp = Array.from({ length: len + 1 }).map(//初始化dp数组 () => Array(size + 1).fill(0) ); //注意我们让i从1开始,因为我们有时会用到i - 1,为了防止数组越界 //所以dp数组在初始化的时候,长度是wight....