就是借用字典的key-value进行的匹配,算法复杂度仅为O(n) 然后还看到了这个 1classSolution(object):2deftwoSum(self, nums, target):34forind, numinenumerate(nums):5iftarget-numinnumsandnums.index(target-num) !=ind:6return[ind, nums.index
Level up your coding skills and quickly land a job. This is the best place to expand your knowledge and get prepared for your next interview.
Problem 11: Leetcode 907 给定一个整数数组 arr,找到 min(b) 的总和,其中 b 的范围为 arr 的每个(连续)子数组。 由于答案可能很大,因此 返回答案模 10^9 + 7 。 举个例子,如果arr = [3,1,2,4],那么输出17,因为它的子数组有[3],[1],[2],[4],[3,1],[1,2],[2,4],[3,1,2],[1,2...
For num = 5 you should return [0,1,1,2,1,2]. Follow up: It is very easy to come up with a solution with run time O(n*sizeof(integer)). But can you do it in linear time O(n) /possibly in a single pass? Space complexity should be O(n). Can you do it like a boss?
Problem 1: Leetcode 40 给定一个数组 candidates 和一个目标数 target ,找出 candidates 中所有可以使数字和为 target 的组合。 candidates 中的每个数字在每个组合中只能使用一次。 比方说candidates = [10,1,2,7,6,1,5], target = 8,那么输出就是 ...
A collection of Python codes for Leetcode Problem of the Day leetcode leetcode-solutions leetcode-practice leetcode-python leetcode-python3 leetcode-solution leetcode-programming-challenges leetcode-solutions-python problem-of-the-day problem-of-the-day-solutions leetcode-potd Updated Dec 23, ...
Hi, I need help understanding this question solution. The problem is https://leetcode.com/problems/find-the-minimum-cost-array-permutation/ Basically we are given a permutation of 0 to n and have to construct another permutation resres that minimizes the function: ∑n−1i=0∣∣res[i]...
Solutions of many LeetCode problems in Java with problem numbers mentioned in the files. java leetcode dsa Updated Jun 2, 2025 Java garyellow / LC-GFG-solution Star 1 Code Issues Pull requests A LeetCode a day keeps the boring away (๑•̀ㅂ•́)و✧ cplusplus leetco...
classSolution{public:stringcompressString(stringS){int i=0,j=0;int n=S.size();string tmp;// 「外层循环」i 指向每个首次出现的字符while(i<n){// 「内层循环」j 向前遍历,直到字符串末尾或找到与 s[i] 不同的字符时跳出while(j<n&&S[i]==S[j])j++;// 压缩字符串,添加至 tmptmp+=S[i]...
解法1:水题。 // Solution 1: Easy. 代码1 // Code 1 416 Partition Equal Subset Sum // #416 平分集合 描述:给定一堆数,判断能否分为两堆,使得两堆的和相等。 // #416 Description: Partition Equal Subset Sum | LeetCode OJ 解法1:背包问题。 // Solution 1: Knapsack Problem. 代码1 // Code...