LeetCode 力扣官方题解 | 449. 序列化和反序列化二叉搜索树 449. 序列化和反序列化二叉搜索树题目描述难易度:中等序列化是将数据结构或对象转换为一系列位的过程,以便它可以存储在文件或内存缓冲区中,或通过网络连接链路传输,以便稍后在同一个或另一个计算机环境中重… ...
简介:【leetcode报错】 leetcode格式问题解决:error: stray ‘\302’ in program [solution.c] 一、情景再现 二、报错原因 该错误是指源程序中有非法字符,需要将非法字符去掉。 一般是由于coder1.使用中文输入法或者2.从别的地方直接复制粘贴代码造成的。 代码中出现了中文空格,中文引号,各种中文标点符号都会出现,...
At first, I am puzzled why this problem would be a hard one. It seems simply applying a BFS would get the answer. So here we go. Brute force, simple BFS Of course it will hit memory limit because I am allocating a 2-dimensional visited array. Assume boolean is 8 bit -> 1B, 1 ...
1classSolution:2defmyAtoi(self, str: str) ->int:3str =str.strip()4strNum =05iflen(str) ==0:6returnstrNum78positive =True9ifstr[0] =='+'orstr[0] =='-':10ifstr[0] =='-':11positive =False12str = str[1:]1314count =015forcharinstr:16ifchar >='0'andchar <='9':17#s...
classSolution{ public: TreeNode*addOneRow(TreeNode*root,intval,intdepth){ //特判depth=1的情况 if(depth==1){ TreeNode*res=newTreeNode(val); res-left=root; returnres; //k记录当前层数 intk=1; queueTreeNode*que; while(que.size())que.pop(); que.push(root); //bfs层序遍历 while(que...
挣扎了一段时间,就去讨论区看解答(https://leetcode.com/problems/strong-password-checker/discuss/91003/O(n%29-java-solution-by-analyzing-changes-allowed-to-fix-each-problem)去了: 代码语言:javascript 代码运行次数:0 运行 复制 class Solution { public int strongPasswordChecker(String s) { int res...
Hi, I need help understanding this question solution. The problem is https://leetcode.com/problems/find-the-minimum-cost-array-permutation/ Basically we are given a permutation of 0 to n and have to construct another permutation resres that minimizes the function: ∑n−1i=0∣∣res[i]...
祖传的手艺不想丢了,所以按顺序写一个leetcode的题解。计划每日两题,争取不卡题吧 3549.两个多项式相乘 3549. 两个多项式相乘 - 力扣(LeetCode)题目给出两个整数数组ploy1和poly2,其中每个数组中下标index的…
1classSolution {2//按行的方式3privatebooleanisOk(char[][] res,inti,intj,intn){//检测位置(i,j)可不可以放置4if(res[i][j] == 'Q')returnfalse;5//列 与行6for(intk = 0; k < n; ++k){7if(k != i && res[k][j] == 'Q')8returnfalse;9if(k != j && res[i][k] ==...
Given n will be a positive integer. Input: 6 Output: 13 Solution: 动态规划的入门题 暴力解法使用搜索,会有大量重复计算 每一步只与前两步有关,所以初始化一二步,之后不断更新前两步的值 Code: Time Complexity: O(n) Spa...