LeetCode 力扣官方题解 | 961. 在长度 2N 的数组中找出重复 N 次的元素 961. 在长度 2N 的数组中找出重复 N 次的元素 题目描述 难易度:简单给你一个整数数组 nums ,该数组具有以下属性: nums.length == 2 * n. nums 包含 n + 1 个 不…阅读全文 赞同5 添加评论 分享收藏...
简介:【leetcode报错】 leetcode格式问题解决:error: stray ‘\302’ in program [solution.c] 一、情景再现 二、报错原因 该错误是指源程序中有非法字符,需要将非法字符去掉。 一般是由于coder1.使用中文输入法或者2.从别的地方直接复制粘贴代码造成的。 代码中出现了中文空格,中文引号,各种中文标点符号都会出现,...
At first, I am puzzled why this problem would be a hard one. It seems simply applying a BFS would get the answer. So here we go. Brute force, simple BFS Of course it will hit memory limit because I am allocating a 2-dimensional visited array. Assume boolean is 8 bit -> 1B, 1 ...
Thought Process This is an easy problem but might be a bit hard to code it up correctly in one pass. We can use a sliding window to keep a rolling sum and compare it with upper and lower bound. A few caveats in implementation: We can simplify using two pointers start and end by kee...
Hi, I need help understanding this question solution. The problem is https://leetcode.com/problems/find-the-minimum-cost-array-permutation/ Basically we are given a permutation of 0 to n and have to construct another permutation resres that minimizes the function: ∑n−1i=0∣∣res[i]...
classSolution(object):defmaxActiveSectionsAfterTrade(self,s,queries):""":type s: str:type queries: List[List[int]]:rtype: List[int]"""n=len(s)intervals=[]p=0one=nwhilep<n:whilep<nands[p]=='1':p+=1ifp==n:breakq=p+1whileq<nands[q]=='0':q+=1intervals.append((p,q-1...
挣扎了一段时间,就去讨论区看解答(https://leetcode.com/problems/strong-password-checker/discuss/91003/O(n%29-java-solution-by-analyzing-changes-allowed-to-fix-each-problem)去了: 代码语言:javascript 代码运行次数:0 运行 复制 class Solution { public int strongPasswordChecker(String s) { int res...
A collection of Python codes for Leetcode Problem of the Day leetcode leetcode-solutions leetcode-practice leetcode-python leetcode-python3 leetcode-solution leetcode-programming-challenges leetcode-solutions-python problem-of-the-day problem-of-the-day-solutions leetcode-potd Updated Dec 23, ...
classSolution{publicint[][]specialGrid(int n){int k=(int)Math.pow(2,n);if(n==0){returnnewint[][]{{0}};}int[][]grid=newint[k][k];fillgrid(grid,0,0,k);returngrid;}int val=0;publicvoidfillgrid(int[][]grid,int x,int y,int size){if(size==1){grid[x][y]=val++;retur...
Given n will be a positive integer. Input: 6 Output: 13 Solution: 动态规划的入门题 暴力解法使用搜索,会有大量重复计算 每一步只与前两步有关,所以初始化一二步,之后不断更新前两步的值 Code: Time Complexity: O(n) Spa...