LeetCode题解之Number of 1 Bits 1、题目描述 2.问题分析 使用C++ 标准库的 bitset 类,将整数转换为 二进制,然后将二进制表示转换为字符串,统计字符串中 1 的个数即可。 3、代码 1inthammingWeight(uint32_t n) {2bitset<32>b(n);3stringb_s =b.to_string() ;45intcount_one =0;6for(string::...
leetcode---Number of 1 Bits Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as theHamming weight). For example, the 32-bit integer ’11' has binary representation00000000000000000000000000001011, so the function should return 3. Credits:...
Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should return 3. 2.解决方案1 AI检测...
Reverse Bits - Binary - Leetcode 190 - Python 呼吸的chou 0 0 Counting Bits - Dynamic Programming - Leetcode 338 - Python 呼吸的chou 0 0 Maximum Product Subarray - Dynamic Programming - Leetcode 152 呼吸的chou 0 0 强推!我愿称之为推荐系统最强实战,基于用户的协同过滤推荐算法实现简单在线...
Explanation: The input binary string 11111111111111111111111111111101 has a total of thirty one '1' bits. Note: Note that in some languages such as Java, there is no unsigned integer type. In this case, the input will be given as signed integer type and should not affect your implementation,...
leetcode.com/problems/number-of-1-bits/ 【问题描述】: 给定一个非负整数n, 返回n的二进制表示中1的个数。 【解题思路】: 在二进制中某一位上不是0就是1,对于一个数值x,如果我们将x的二进制表示整体左移1位,则新的数值是2x. 也就是说对于一个数n, 假设n可以被2整除,则n的二进制中1的个...
Line 1061: Char 9: runtime error: addition of unsigned offset to 0x7ffdd1b0d720 overflowed to 0x7ffdd1b0d71e (basic_string.h) SUMMARY: UndefinedBehaviorSanitizer: undefined-behavior /usr/bin/../lib/gcc/x86_64-linux-gnu/9/../../../../include/c++/9/bits/basic_string.h:1070:9 ...
363 Max Sum of Rectangle No Larger Than K Hard Solution 364 Nested List Weight Sum II Medium Solution 365 ? ? Solution 366 Find Leaves of Binary Tree Medium Solution 367 Valid Perfect Square Easy Solution 368 Largest Divisible Subset Medium Solution 369 Plus One Linked List Medium Solution 370...
1. Description Sort Integers by The Number of 1 Bits 2. Solution 解析:由于最大数字不超过10000,因此1的位数不超过14位,注意+=的运算优先级要低于&,而+的运算优先级要高于&。Version 1用右移运算获得1的个数,Version 2用的bin函数,Version 3通过python自带的排序函数进行排序。Version 4使用字典保存结果。
计算高度,width(两边柱子距离-1)和height(木桶短板-底部),加到结果里去。 class Solution { public: int trap(vector<int>& height) { if(height.empty()) return 0; height.push_back(0); int res =0; stack<int> st;//decreasing stack