LeetCode题解之Number of 1 Bits 1、题目描述 2.问题分析 使用C++ 标准库的 bitset 类,将整数转换为 二进制,然后将二进制表示转换为字符串,统计字符串中 1 的个数即可。 3、代码 1inthammingWeight(uint32_t n) {2bitset<32>b(n);3stringb_s =b.to_string() ;45intcount_one =0;6for(string::...
Write a function that takes an unsigned integer and return the number of '1' bits it has (also known as the Hamming weight).Example:Input: 00000000000000000000000000001011 Output: 3 Explanation: The input binary string 00000000000000000000000000001011 has a total of three '1' bits. Example 2: ...
LeetCode Top Interview Questions 191. Number of 1 Bits (Java版; Easy) 题目描述 Write a function that takes an unsigned integer and return the number of '1' bits it has (also known as the Hamming weight). Example 1: Input: 00000000000000000000000000001011 Output: 3 Explanation: The input bin...
https://leetcode.com/problems/number-of-1-bits/description/ 题目描述 Write a function that takes an unsigned integer and return the number of '1' bits it has (also known as the Hamming weight). Example 1: Input: 00000000000000000000000000001011 Output: 3 Explanation: The input binary string ...
Explanation: The input binary string00000000000000000000000000001011 has a total of three '1' bits. 1. Example 2: Input: 00000000000000000000000010000000 Output: 1 Explanation: The input binary string 00000000000000000000000010000000 has a total of one '1' bit. ...
Input: n = 11111111111111111111111111111101 Output: 31 Explanation: The input binary string 11111111111111111111111111111101 has a total of thirty one '1' bits. 解题思路1 方法一: 暴力求解, 将二进制数变成字符串, 遍历 示例代码1 def hammingWeight(n: int) -> int: n = format(n, "032b") coun...
[LeetCode] 233. Number of Digit One 数字1的个数Given an integer n, count the total number of digit 1 appearing in all non-negative integers less than or equal to n. For example: Given n = 13, Return 6, because digit 1 occurred in the following numbers: 1, 10, 11, 12, 13. ...
Given an integern, countthe total number of digit1appearing in all non-negative integers less than or equal ton. Example 1: Input:n = 13Output:6 Example 2: Input:n = 0Output:0 Constraints: 0 <= n <= 109 Accepted 113.4K Submissions ...
Can you solve this real interview question? Number of Digit One - Given an integer n, count the total number of digit 1 appearing in all non-negative integers less than or equal to n. Example 1: Input: n = 13 Output: 6 Example 2: Input: n = 0 O
191 Number of 1 Bits https://leetcode-cn.com/problems/number-of-1-bits/ https://leetcode.com/problems/number-of-1-bits/description/ Write a function that takes an unsigned integer and return the number of '1' bits it has (also known as the Hamming weight). ...