AI代码解释 classSolution:defletterCombinations(self,digits):""":type digits:str:rtype:List[str]"""ifnot digits:return[]digit2chars={'2':'abc','3':'def','4':'ghi','5':'jkl','6':'mno','7':'pqrs','8':'tuv','9':'wxyz'}res=[iforiindigit2chars[digits[0]]]foriindigits[1:]:res=[m+nforminresfor...
来自专栏 · Leetcode力扣刷题笔记 Given a string containing digits from 2-9 inclusive, return all possible letter combinations that the number could represent. Return the answer in any order. A mapping of digit to letters (just like on the telephone buttons) is given below. Note that 1 does...
代码如下。 #defineNOD(x) ((int)log10(x) + 1)//Number of digits of x.#definePOT(x) ((int)pow(10, NOD(x) - 1))//The maximum power of ten it contains. POT(700) = 100, POT(2900) = 1000#defineHIGH(x) ((int)x / POT(x))//Top digit.#defineSH(x) ((int)(x / (POT(...
先取第1个数字,得到字母组合;然后再将第一个字母组合中的字母分别插入到后续数字组成的字母答案中,以示例1做如下解释: digits的第一个数字为'2',其代表的字母组合为'a' 'b' 'c';digits的后续所有数字为'3',它的字母组合为['d','e','f'],故将第一个数字'2'的字母组合'a' 'b' 'c'分别插入到['...
LeetCode No.258 Add Digits LeetCode Algorithum NO.258(2015.10.26 16:09:00) Given a non-negative integer num,repeatedly add all its digits until the result has only one digit. For example: Givennum = 38, the process is like:3 + 8 = 11,1 + 1 = 2. Since2has only one digit, ...
Leetcode No.88 Merge Sorted Array(c++实现) 1. 题目 1.1 英文题目 You are given two integer arrays nums1 and nums2, sorted in non-decreasing order, and two integers m and n, representing the number of elements in nums1 and nums2 respectively. ...
for value, symbol in digits: # We don't want to continue looping if we're done. if num == 0: break count, num = divmod(num, value) # Append "count" copies of "symbol" to roman_digits. roman_digits.append(symbol * count) ...
405 Convert a Number to Hexadecimal Python Java Two's complement 1. Bit manipulate, each time handle 4 digits2. Python (hex) and Java API (toHexString & Integer.toHexString) 408 Valid Word Abbreviation ♥ Python Go over abbr and word, O(n) and O(1) 409 Longest Palindrome Python Java ...
LeetcodeInJS--String(持续更新) 709 toLowerCase 难度:easy 标签:ASCII码 初始思路:大写字母ASCII范围65-90,小写字母ASCII范围97-122,func_大写转小写即为val+32 resultStr = '' for(str) { if (str[i] in 大写字母ASCII码范围) { resultStr + = func_大写转小写(str[i])...
1281- subtract-the-product-and-sum-of-digits-of-an-integer 0461、0477、1281 solved May 6, 2020 1351-count-negative-numbers-in-a-sorted-matrix 1351 solved May 4, 2020 Interview053-I- Find-Number-In-Sort-Array-I fix: fix Interview053 format Apr 18, 2020 Pictures 整理部分文件 Apr 16, 20...