1.Number of 1 Bits 本题收获: 1.Hamming weight:即二进制中1的个数 2.n &= (n-1)【n = n & (n-1)】的用处 题目: Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as theHamming weight). For example, the 32-bit integer ’11...
Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as theHamming weight).For example, the 32-bi
Write a function that takes an unsigned integer and returns the number of ’1’ bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11’ has binary representation 00000000000000000000000000001011, so the function should return 3. 本题难度Easy。有2...
https://leetcode-cn.com/problems/number-of-1-bits/description/ 题目描述 编写一个函数,输入是一个无符号整数,返回其二进制表达式中数字位数为 ‘1’ 的个数(也被称为汉明重量)。 示例: 输入:00000000000000000000000000001011 输出:3 解释:输入的二进制串 00000000000000000000000000001011 中,共有三位为 '1'。
今天介绍的是LeetCode算法题中Easy级别的第45题(顺位题号是191)。编写一个带无符号整数的函数,并返回它所具有的“1”位数。例如: 输入:11 输出:3 说明:整数11具有二进制表示00000000000000000000000000001011 输入:128 输出:1 说明:整数128具有二进制表示00000000000000000000000010000000 ...
题目链接: Number of 1 Bits : https://leetcode.com/problems/number-of-1-bits/ 位1的个数: https://leetcode.cn/problems/number-of-1-bits/ LeetCode 日更第132天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满
Write a function that takes an unsigned integer and return the number of '1' bits it has (also known as theHamming weight). 输入是一个无符号整数,返回其二进制表达式中数字位数为 ‘1’ 的个数。 解析 消除最后的1 观察一下 n 与 n-1 这两个数的二进制表示:对于 n-1 这个数的二进制来说,...
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1. Description Sort Integers by The Number of 1 Bits 2. Solution 解析:由于最大数字不超过10000,因此1的位数不超过14位,注意+=的运算优先级要低于&,而+的运算优先级要高于&。Version 1用右移运算获得1的个数,Version 2用的bin函数,Version 3通过python自带的排序函数进行排序。Version 4使用字典保存结果。
来源：力扣（LeetCode）链接：https://leetcode-cn.com/problems/number-of-1-bits/著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。解法一：遍历 首先，用Integer.toBinaryString(num)方法将n转化为二进制字符串binaryString；然后，遍历字符串binaryString的每一个字符，判断当前字符是否是'1'...