LeetCode题解之Number of 1 Bits 1、题目描述 2.问题分析 使用C++ 标准库的 bitset 类,将整数转换为 二进制,然后将二进制表示转换为字符串,统计字符串中 1 的个数即可。 3、代码 1inthammingWeight(uint32_t n) {2bitset<32>b(n);3stringb_s =b.to_string() ;45intcount_one =0;6for(string::...
leetcode---Number of 1 Bits Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as theHamming weight). For example, the 32-bit integer ’11' has binary representation00000000000000000000000000001011, so the function should return 3. Credits:...
leetcode 191. Number of 1 Bits 数字中1的数量 + 位运算 Write a function that takes an unsigned integer and returns the number of ’1’ bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11’ has binary representation 00000000000000000000000000001011, so the f...
[LeetCode]Number of 1 Bits Question Write a function that takes an unsigned integer and returns the number of ’1’ bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11’ has binary representation 00000000000000000000000000001011, so the function ...
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Leetcode 191. Number of 1 Bits 题目描述:统计二进制中1的位数。 题目链接:191. Number of 1 Bits 初步想法就是沿用上题190的思路,右移n,然后不断按位与操作来进行计数。 当然也可以用我以前面试的时候答的转成字符串哈哈哈~ 参考链接 191. Number of 1 Bits | 汉明重量几种解法......
[LeetCode] Sparse Matrix Multiplication 稀疏矩阵相乘 Given two sparse matrices A and B, return the result of AB. You may assume that A's column number is ... 537 Complex Number Multiplication 复数乘法 详见:https://leetcode.com/problems/complex-number-multiplication/description/ C++: class ...
Sort Integers by The Number of 1 Bits 2. Solution 解析:由于最大数字不超过10000,因此1的位数不超过14位,注意+=的运算优先级要低于&,而+的运算优先级要高于&。Version 1用右移运算获得1的个数,Version 2用的bin函数,Version 3通过python自带的排序函数进行排序。Version 4使用字典保存结果。
191. Number of 1 Bits 题目: https://leetcode.com/problems/number-of-1-bits/ 难度: Easy 转成二进制,数1的个数
输入:n = 3, k = 2 输出:3 解释:[1,3,2], [2,3,1] 和 [2,1,3] 是仅有的能满足恰好 2 根木棍可以看到的排列。可以看到的木棍已经用粗体+斜体标识。 示例2: 输入:n = 5, k = 5 输出:1 解释:[1,2,3,4,5] 是唯一一种能满足全部 5 根木棍可以看到的排列。可以看到的木棍已经用粗体...