Merge all the linked-lists into one sorted linked-list and return it. Example 1: Input:lists = [[1,4,5],[1,3,4],[2,6]]Output:[1,1,2,3,4,4,5,6]Explanation:The linked-lists are: [ 1->4->5, 1->3->4, 2->6 ] merging
intcnt=0; for(inti=0;i<old_lists.size()/2;i++) { new_lists.push_back(mergeTwoLists(old_lists[cnt],old_lists[cnt+1])); cnt+=2; } if(cnt<old_lists.size())//如果链表数是奇数,则合并完前面的两两组合后,还要加入最后一个链表 new_lists.push_back(old_lists[cnt]); old_lists.cle...
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 思路:合并k路有序链表,可以用最小堆,然后每次送入堆中,取出最小的,并将该链表下一值取出放入 1、使用优先级队列模拟小根堆 /** * Definition for singly-linked list. * struct ListNode { * int va...
//方法2 使用分治 public static ListNode mergeKLists(ListNode[] lists) { if (lists == null || lists.length == 0) return null; return merge(lists, 0, lists.length - 1); } public static ListNode merge(ListNode[] lists, int left, int right) { if (left == right) return lists[left...
* }; */ class Solution { public: ListNode* mergeKLists(vector<ListNode*>& lists) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2Case 3 lists = [[1,4,5],[1,3,4],[2,6]] 1 2 3 [[1,4,5],[1,3,4],[2,6]] [] [[]] Source 布局...
// 登录 AlgoMooc 官网获取更多算法图解 // https://www.algomooc.com // 作者:程序员吴师兄 public class Solution { public ListNode mergeKLists(ArrayList<ListNode> lists) { // 队列是遵循先进先出(First-In-First-Out)模式的,但有时需要在队列中基于优先级处理对象。 // PriorityQueue 和队列 Qu...
mergeTwoLists 使我们在两个链表合并中的最佳解法,这里复用了一下。 效果 Runtime: 98 ms, faster than 16.31% of Java online submissions for Merge k Sorted Lists. Memory Usage: 41.4 MB, less than 47.50% of Java online submissions for Merge k Sorted Lists. 改善效果不是很明显。 那么如何改进呢?
*/funcmergeKLists(lists[]*ListNode)*ListNode{k:=len(lists)ifk==0{returnnil}fork>1{ifk%2==1{lists[0]=merge(lists[0],lists[k-1])}k/=2fori:=0;i<k;i++{lists[i]=merge(lists[k+i],lists[i])}}returnlists[0]}funcmerge(l1,l2*ListNode)*ListNode{h:=&ListNode{}tmp:=hforl1!
Can you solve this real interview question? Merge k Sorted Lists - You are given an array of k linked-lists lists, each linked-list is sorted in ascending order. Merge all the linked-lists into one sorted linked-list and return it. Example 1: Inpu
LeetCode题解-合并K个有序数组-Java 利用21题合并两个有序数组的代码,使用for循环进行合并,效率较低;参照第一名的代码,使用分治,改变对数组的处理方法,可以大幅度提高处理效率: 修改后: publicListNodemergeKLists(ListNode[] lists){if(lists==null||lists.length==0)returnnull;returnsort(lists,0, lists....