## 解法二:递归 Recursion class Solution: def mergeTwoLists(self, head1, head2): ## head1 和 head2 头结点指代两个链表 ## 递归的 base,结束条件 if head1 is None: return head2 elif head2 is None: return head1 elif head1.val < head2.val: ## 把小的值 head1 提取出来,拼接上后面...
Can you solve this real interview question? Merge Two Sorted Lists - You are given the heads of two sorted linked lists list1 and list2. Merge the two lists into one sorted list. The list should be made by splicing together the nodes of the first two li
1、题目描述 2、题目分析 题目要求合并有序的两个链表,要求不能额外申请空间。 3、代码 1ListNode* mergeTwoLists(ListNode* l1, ListNode*l2) {2if( l1 == NULL )returnl2;3if( l2 == NULL )returnl1;4if( l1 == NULL && l2 == NULL )returnNULL;5ListNode* r = ( l1->val <= l2->val )...
参考链接:https://leetcode.com/problems/merge-two-sorted-lists/discuss/9814/3-lines-c-12ms-and-c-4ms。参考代码如下: class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if (!l1 || (l2 && l1->val > l2->val)) swap(l1, l2); if (l1) l1->next = ...
next = list2; } // 返回合并后的链表的头结点 head_pre.next } } 题目链接: Merge Two Sorted Lists : leetcode.com/problems/m 合并两个有序链表: leetcode-cn.com/problem LeetCode 日更第 52 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满...
https://leetcode.com/problems/merge-two-sorted-lists/ 题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 思路: easy 。 算法: AI检测代码解析 ...
leetcode -- Merge Two Sorted Lists -- 重点 https://leetcode.com/problems/merge-two-sorted-lists/ 我的思路就是找到第一个j > i的,然后用pre_j串起来。然后相应地对i再做一次。这种思路不太好。 note在指针前进的时候,判断越界的语句要放在if 或者while的前半部分。
class ListNode: def __init__(self, x): self.val = x self.next = None class Solution: def mergeTwoLists(self, l1: ListNode, l2: ListNode) -> ListNode: head = ListNode(0) first = head while l1 and l2: if l1.val > l2.val: head.next = l2 l2 = l2.next else: head.next =...
Merge Two Sorted Lists 二、解题 两个有序链表的排序。 三、尝试与结果 classSolution(object):defmergeTwoLists(self,l1,l2):ret=ListNode(0)ifl1==None:returnl2ifl2==None:returnl1ifl1.val<l2.val:ret=l1 ret.next=self.mergeTwoLists(l1.next,l2)else:ret=l2 ...
21、Merge Two Sorted Lists 2016-05-28 15:58 −1 ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { 2 ListNode* t; 3 t=(ListNode*)malloc(sizeof(ListNode)); 4 ListNode *t1; 5 ... 不小的文 0 160 Leetcode 21 - Merge Two Sorted Lists ...