classSolution{public:vector<int>intersection(vector<int>& nums1, vector<int>& nums2){sort(nums1.begin(), nums1.end());sort(nums2.begin(), nums2.end());// merge two sorted arraysvector<int> ret;inti =0, j =0;while(i < nums1.size() && j < nums2.size()) {if(nums1[i] ...
Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 =[1,2,2,1], nums2 =[2,2] Output:[2,2] Example 2: Input: nums1 =[4,9,5], nums2 =[9,4,9,8,4] Output:[4,9] Note: Each element in the result should appear as many times as it ...
Intersection of Two Arrays II Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be i...
Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any order. Follow up: What if the given array is already sorted? How w...
res.push_back(nums1[i]);++i; ++j; }elseif(nums1[i] >nums2[j]) {++j; }else{++i; } }returnres; } }; 两个数组相交之二[LeetCode] Intersection of Two Arrays II,如需转载请自行联系原博主。
2. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any order. Follow up: What if the given array is already sorted? How would you optimize your algorithm? What ifnums1's size is small compared tonums2's size? Which al...
Given two integer arrays nums1 and nums2, returnan array of their intersection. Each element in the result must appear as many times as it shows in both arrays and you may return the result inany order. Example 1:Input:nums1 = [1,2,2,1], nums2 = [2,2]Output:[2,2] ...
42 -- 7:56 App LeetCode力扣 2. 两数相加 Add Two Numbers 16 -- 9:25 App LeetCode力扣 350. 两个数组的交集 II Intersection of Two Arrays II 104 -- 9:07 App LeetCode力扣 509. 斐波那契数 Fibonacci Number 89 -- 7:44 App LeetCode力扣 56. 合并区间 Merge Intervals 104 -- 6:32...
Each element in the result should appear as many times as it shows in both arrays. The result can be in any order. Follow up: What if the given array is already sorted? How would you optimize your algorithm? What if nums1's size is small compared to num2's size? Which algorithm is...
Case 1Case 2 arr1 = [1,2,3,4,5] arr2 = [1,2,5,7,9] arr3 = [1,3,4,5,8] 1 2 3 4 5 6 [1,2,3,4,5] [1,2,5,7,9] [1,3,4,5,8] [197,418,523,876,1356] [501,880,1593,1710,1870] [521,682,1337,1395,1764] Source 该题目是 Plus 会员专享题 感谢使用力扣...