leetcode【数组】---349. Intersection of Two Arrays(两个数组的交集),程序员大本营,技术文章内容聚合第一站。
leetcode【数组】---349. Intersection of Two Arrays(两个数组的交集) 1、题目描述 2、分析 给定两个数组,编写一个函数来计算它们的交集。可以从例子上看出,这道题只需要找到两个数组中相同的数字就好,所以现将第一个数组放入一个set,set里没有重复的元素,并且是排好序的。之后遍历第二个数组看第二个数组...
1、这道题给定两个vector,要求返回两个vector的交集,比如nums1=[1,2,2,1],nums2=[2,2],返回的交集是[2,2],其中有多少个相同的元素就返回多少个。返回的交集不讲究顺序。 2、这道题看完题意,熟悉leetcode的同学应该会马上想到先排序,排序之后的两个vector来比较,时间复杂度会下降很多。 如果不排序,那就...
LeetCode-Intersection of Two Arrays II Description: Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] O......
Sort both arrays, use two pointers Time complexity: O(nlogn) 1publicclassSolution {2publicint[] intersection(int[] nums1,int[] nums2) {3Set<Integer> set =newHashSet<>();4Arrays.sort(nums1);5Arrays.sort(nums2);6inti = 0;7intj = 0;8while(i < nums1.length && j <nums2.length...
Hold住Leetcode——Intersection of Two Arrays Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. Subscribe to see ...
Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: 1、Each element in the result must be unique. 2、The result can be in any order. 要完成的函数: vector<int> intersection(vector<int>& ...
350. 两个数组的交集 II Intersection of Two Arrays II难度:Easy| 简单 相关知识点:排序 哈希表 双指针 二分查找题目链接:https://leetcode-cn.com/problems/intersection-of-two-arrays-ii/官方题解:https://leetcode-cn.com/problems/intersection-of-
Can you solve this real interview question? Intersection of Two Arrays II - Given two integer arrays nums1 and nums2, return an array of their intersection. Each element in the result must appear as many times as it shows in both arrays and you may retur
Leetcode 350:Intersection of Two Arrays II Given two arrays, write a function to compute their intersection. 说人话: 求两个数组的交集。 举例1: 举例2: [法1] Map 记录频次 思路 因为是求交集,所以元素出现的次数是需要进行考虑了。这里笔者考虑到用 Map 这个集合框架来解决这个问题,主要是基于 key-...