classSolution{public:vector<int>intersection(vector<int>& nums1, vector<int>& nums2){sort(nums1.begin(), nums1.end());sort(nums2.begin(), nums2.end());// merge two sorted arraysvector<int> ret;inti =0, j =0;while(i < nums1.size() && j < nums2.size()) {if(nums1[i] ...
Here is the most important observation in order to solve this problem. Both arrays ARE sorted. This provides a very important clue. We must make full use of this information that they ARE in fact sorted. We can have two index, which both starts at zero. Compare the two first elements of...
The union of these arrays would be: [1, 2, 3, 4, 5, 6, 7, 8] Intersection of Two Sorted Arrays: The intersection of two sorted arrays is an operation that yields a new sorted array containing only the common elements between the two arrays. The resulting array will contain elements ...
Find intersection of two arrays video tutorial //Single iteration code public class Intersection { public static void main(String[] args) { int arr1[] = {2, 6, 7, 8, 9}; int arr2[] = {6, 9, 10}; /** Take two indexes, and initialize with zero. */ int i = 0; int j = ...
349. Intersection of Two Arrays # 题目# Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] Note: Each element...
Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] 1 2 Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any order. Follow up: What if the given array is already sorted? How would you op...
Each element in the result should appear as many times as it shows in both arrays. The result can be in any order. Follow up: What if the given array is already sorted? How would you optimize your algorithm? What if nums1's size is small compared to num2's size? Which algorithm is...
Each element in the result should appear as many times as it shows in both arrays. The result can be in any order. Follow up: What if the given array is already sorted? How would you optimize your algorithm? What if nums1’s size is small compared to nums2’s size? Which algorithm...
2. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any order. Follow up: What if the given array is already sorted? How would you optimize your algorithm? What ifnums1's size is small compared tonums2's size? Which al...
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