先将两数组排序,然后使用双指针,依次判断两数组中的元素是否相等,如果某个元素大于或小于另外一个元素,则将指针向后移动,如果相等,则将元素放入ArrayList中,然后将ArrayList中的元素迭代放入数组,最后返回。 因为使用Arrays类的sort方法,所以时间复杂度是O(n log(n)),空间复杂度是O(n)。 publicint[]intersect(int...
2、分析 给定两个数组,编写一个函数来计算它们的交集。 这道题和上道题很像,但是相比较而言,上道题只需要输出重复的一个元素就行,所以上道题可以采用set。这道题可以将数组nums1存入一个哈希表,数组的值和这个值出现的次数构成一组对应元素,然后遍历数组2,如果哈希表中这个值为0代表没有这个元素,如果不为0则...
1// 350. Intersection of Two Arrays II 2// https://leetcode.com/problems/intersection-of-two-arrays-ii/description/ 3// 时间复杂度: O(nlogn) 4// 空间复杂度: O(n) 5class Solution { 6public: 7 vector<int>intersect(vector<int>& nums1, vector<int>& nums2) { 8 9 map<int,int>...
Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] Note: Each element in the result should appear as many times...
Counter计数:如果nums2中的元素在counter中计数大于0,则添加到res中,并且计数减1; classSolution(object):defintersect(self,nums1,nums2):""" :type nums1: List[int] :type nums2: List[int] :rtype: List[int] """fromcollectionsimportCounter ...
1. Description Intersection of Two Arrays II 2. Solution Version 1 classSolution:defintersect(self,nums1,nums2):nums1.sort()nums2.sort()m=len(nums1)n=len(nums2)i=0j=0result=[]whilei<mandj<n:ifnums1[i]<nums2[j]:i+=1elifnums1[i]>nums2[j]:j+=1else:result.append(nums1[i]...
https://leetcode.com/problems/intersection-of-two-arrays-ii/ Given two arrays, write a function to compute their intersection. Example: Givennums1=[1,2,2,1],nums2=[2,2], return[2,2]. Note: Each element in the result should appear as many times as it shows in both arrays. ...
[LeetCode] Intersection of Two Arrays 两个数组相交 Given two arrays, write a function to compute their intersection. Example: Givennums1=[1, 2, 2, 1],nums2=[2, 2], return[2]. Note: Each element in the result must be unique.
[LeetCode] Intersection of Two Arrays I & II Intersection of Two Arrays I Problem Given two arrays, write a function to compute their intersection. Example Givennums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note Each element in the result must be unique....
https://leetcode.com/problems/intersection-of-two-arrays/ 中文版描述 给定两个数组 nums1 和 nums2 ,返回 它们的交集 。输出结果中的每个元素一定是 唯一 的。我们可以 不考虑输出结果的顺序。 示例1: 输入:nums1 = [1,2,2,1], nums2 = [2,2] 输出:[2] 示例2: 输入:nums1 = [4,9,5], ...