a.player_id, datediff(b.event_date,a.first_log_date) as time1 from ( select player_id, min(event_date) as first_log_date from Activity group by player_id )a left join ( select player_id, event_date from Activity group by player_id,event_date )b on a.player_id=b.player_id gro...
0550 Game Play Analysis IV 45.2% Medium 0551 Student Attendance Record I 46.0% Easy 0552 Student Attendance Record II 36.7% Hard 0553 Optimal Division 56.7% Medium 0554 Brick Wall 50.0% Medium 0555 Split Concatenated Strings 42.2% Medium 0556 Next Greater Element III 31.7% Medium 0557...
To account for this, there should exist another "play mode" (perhaps that is unlocked only after a scenario is completed for the first time): retesting the player's solution with a random seed. This is analogous to how Leetcode will test a solution against hidden inputs as well as publi...
fuxuemingzhu#Leetcode-Solution-All#55. Jump Game 跳跃游戏1 Yo**ke上传leetcode 1.贪心算法中,作出的每步贪心决策都无法改变,因为贪心策略是由上一步的最优解推导下一步的最优解,而上一步之前的最优解则不作保留 2.由(1)中的介绍,可以知道贪 (0)踩踩(0) 所需:1积分...
leetcode / solution / 0000-0099 / 0055.Jump Game / README_EN.md README_EN.md 2.58 KB 一键复制 编辑 原始数据 按行查看 历史 ylb 提交于 4年前 . feat: add solutions to lc problem: No.0055. Jump Game 55. Jump Game Description Solutions Python3 Java C++ Go C# 55....
55. 跳跃游戏 - 给你一个非负整数数组 nums ,你最初位于数组的 第一个下标 。数组中的每个元素代表你在该位置可以跳跃的最大长度。 判断你是否能够到达最后一个下标,如果可以,返回 true ;否则,返回 false 。 示例 1: 输入:nums = [2,3,1,1,4] 输出:true 解释
* @lc app=leetcode id=45 lang=cpp * * [45] Jump Game II */ // @lc code=start class Solution { // assume that you can always reach the last index. public: int jump(vector<int>& nums) { assert(!nums.empty()); if (nums.size() == 1) return 0; ...
leetcode / solution / 0000-0099 / 0045.Jump Game II / README_EN.md README_EN.md2.78 KB 一键复制编辑原始数据按行查看历史 ylb提交于4年前.feat: add solutions to lc problem: No.0045. Jump Game II 45. Jump Game II 中文文档 Description ...
😏 LeetCode solutions in any programming language | 多种编程语言实现 LeetCode、《剑指 Offer(第 2 版)》、《程序员面试金典(第 6 版)》题解 - leetcode/solution/1300-1399/1306.Jump Game III/README.md at main · lei1024/leetcode
class Solution { static int ans = 0; public int maxJumps(int[] arr, int d) { ans = 0; int length = arr.length; int count = 0; int[] dp = new int[length]; PriorityQueue<Integer> p = new PriorityQueue<Integer>(); ...