FindHeaderBarSize FindTabBarSize You are keeping the scores for a baseball game with strange rules. At the beginning of the game, you start with an empty record. You are given a list of stringsoperations, whereoperations[i]is theithoperation you must apply to the record and is one of the...
来自专栏 · LeetCode 每日一题 题意 给定一个操作列表 ops ,在一个空的分数列表 record 中按顺序执行这些操作,返回最终的分数列表 record 中所有分数之和。 操作op 有以下 4 种: 整数:将该整数放入 record "+" :将 record 中的最后两个整数相加,并将结果放入 record "D" :将 record 中的最后一个整数...
题目地址:https://leetcode.com/problems/baseball-game/description/题目描述You’re now a baseball game point recorder.Given a list of strings, each string can be one of the 4 following types:Integer (one round’s score): Directly represents the number of points you get in this round. "+"...
You're now a baseball game point recorder. Given a list of strings, each string can be one of the 4 following types: Integer(one round's score): Directly represents the number of points you get in this round. "+"(one round's score): Represents that the points you get in this round...
682. Baseball Game ...[682] Baseball Game Java 原题链接:LeetCode题目682 Baseball Game 题目简述:实现一个网球计分器,根据输入的一系列计分字符串,输出最终得分。其中计分字符串分为4种类型: (1)整型,表示本轮有效分数为该整数; (2)“+”,表示本轮有效分数=前两轮有效分数之和; (3)“D”,表示本...
package leetcode import "strconv" func calPoints(ops []string) int { stack := make([]int, len(ops)) top := 0 for i := 0; i < len(ops); i++ { op := ops[i] switch op { case "+": last1 := stack[top-1] last2 := stack[top-2] stack[top] = last1 + last2 top...
LeetCode 棒球比赛(Baseball Game) 你现在是棒球比赛记录员。 给定一个字符串列表,每个字符串可以是以下四种类型之一: 1.整数(一轮的得分):直接表示您在本轮中获得的积分数。 “+”(一轮的得分):表示本轮获得的得分是前两轮有效回合得分的总和。 “D”(一轮的得分):表示本轮获得的得分是前一轮有效回合得分...
[leetcode] 682. Baseball Game Description You’re now a baseball game point recorder. Given a list of strings, each string can be one of the 4 following types: Integer (one round’s score): Directly represents the number of points you get in this round....
class Solution { public int calPoints(String[] ops) { int[]arr=new int[ops.length]; int i=0; for (String s : ops) { switch(s){ case "+":arr[i]=arr[i-1]+arr[i-2];i++;break; case "D":arr[i]=arr[i-1]*2;i++;break; case "C":arr[i-1]=0;i--;break; default...
public class Solution { public int CalPoints(string[] ops) { StackByLink stack = new StackByLink(); for (int i = 0; i < ops.Length; i++) { var op = ops[i]; switch (op) { case "C": stack.Pop(); break; case "D": stack.Push(stack.Print() * 2); break; case "+":...