classSolution{public:voidgameOfLife(vector<vector<int>>& board){if(board.size()==0||board[0].size()==0)return;intm=board.size();intn=board[0].size();int* NextTurnBoard=newint[m*n];//为了保证同时进行更新,这里新建一个地图for(inti=0;i<m;i++){for(intj=0;j<n;j++){ NextTur...
【leetcode_medium】289. Game of Life leetcode_medium_array problem 289. Game of Life solution #1: code 注意: 1) 理解题意,将问题转换为数学可解问题; 2) 状态机的转换状态,以及最后的结果的关系; 3) 可以采用移位操作; 1 2 3 4 5 6 7 /* 状态: 前一位表示下一代的状态,后一位表示当前的...
// 8 个方向的位置改变量 var dr = []int{-1, -1, 0, 1, 1, 1, 0, -1}; var dc = []int{0, 1, 1, 1, 0, -1, -1, -1}; func gameOfLife(board [][]int) { m := len(board) n := len(board[0]) // 枚举每一个细胞 for r := 0; r < m; r++ { for c :=...
题目地址:https://leetcode.com/problems/game-of-life/description/ According to the Wikipedia’s article: “The Game of Life, also known simply as Life, is a cellular automaton devised by the British mathematician John Horton Conway in 1970.” Given a board withmbyncells, each cell has an ...
289. Game of Life刷题笔记 问题描述签到题,拿两个队列来存放要改变的值即可 LeetCode代码: class Solution: def gameOfLife(self, board: List[List[int]]) -> None: """ Do not return anything, modify board in-place instead. """ m = len(board)...
4、解题方法 在不使用定义新矩阵的情况下,要想解决本问题就需要先定义一 组中间状态,中间状态要求能看出一个单元格变化前后两方面的生死 情况。Java 代码如下: /** * @功能说明:LeetCode 289 - Game of Life * @开发人员:Tsybius2014 * @开发时间:2015 年 10 月 8 日 */ public class Solution { ...
* @功能说明:LeetCode 289 - Game of Life * @开发人员:Tsybius2014 * @开发时间:2015年10月8日 */ public class Solution { //死亡单位 final int DEAD = 0; //存活单位 final int ALIVE = 1; //变化情况:死亡→死亡 final int DEAD_TO_DEAD = 0; ...
【Leetcode】Game of Life https://leetcode.com/problems/game-of-life/ 题目: According to theWikipedia's article: "The Game of Life, also known simply as Life, is a cellular automaton devised by the British mathematician John Horton Conway in 1970."...
class Solution{public:voidgameOfLife(vector<vector<int>>&board){if(board.empty())return;vector<int>dx{0,0,1,-1,1,1,-1,-1},dy{1,-1,0,0,1,-1,1,-1};;for(inti=0;i<board.size();i++)for(intj=0;j<board[0].size();j++){intcount=0;for(intk=0;k<8;k++){intx=i+dx...
LeetCode 力扣官方题解 | 289. 生命游戏 力扣(LeetCode) 已认证账号 289. 生命游戏 Game of Life 难度:Medium| 中等 相关知识点:数组 题目链接:https://leetcode-cn.com/problems/game-of-life/ 官方题解:https://leetcode-cn.com/problems/game-of-life/solution/ ...