https://github.com/grandyang/leetcode/issues/114 类似题目: Flatten a Multilevel Doubly Linked List 参考资料: https://leetcode.com/problems/flatten-binary-tree-to-linked-list/ https://leetcode.com/problems/flatten-binary-tree-to-linked-list/discuss/37182/my-recursive-solution-is-easy-and-clean...
反正是复杂了。 voidflatten(structTreeNode*root) {if(root == NULL)return; flatten(root->left); flatten(root->right);if(root->left) {structTreeNode *p = root->left;while(p ->right) { p= p->right; } p->right = root->right; root->right = root->left; root->left =NULL; }retu...
https://leetcode.com/problems/flatten-binary-tree-to-linked-list/ 题目: Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 思路: 递归处理每个结点,如果结点左孩...
理解上面代码过后就容易理解:LeetCode | Flatten Binary Tree to Linked List(二叉树转化成链表) C/C++基本语法学习 STL C++ primer
114. Flatten Binary Tree to Linked List # 题目 # Given a binary tree, flatten it to a linked list in-place. For example, given the following tree: 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 题目大意 # 给定一个
Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 递归法 思路 相当于一次先序遍历, 将先访问的点存储在数组里, 下一个访问的节点为之前访问的点的右子树 ...
Given a binary tree, flatten it to a linked list in-place. For example, given the following tree: 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 First 根据栈的思想,通过深度优先遍历将所有的节点退出栈中,再由栈弹出每个节点进行拼接 ...
Given a binary tree, flatten it to a linked list in-place. For example, Given 代码语言:javascript 复制 1/\25/\ \346 The flattened tree should look like: 代码语言:javascript 复制 1\2\3\4\5\6 click to show hints. Anwser 1 : ...
Flatten Binary Tree to Linked List 2. Solution /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; ...
Given a binary tree, flatten it to a linked list in-place. For example, given the following tree: {代码...} The flattened tree should look like: {...