Flatten a Multilevel Doubly Linked List 参考资料: https://leetcode.com/problems/flatten-binary-tree-to-linked-list/ https://leetcode.com/problems/flatten-binary-tree-to-linked-list/discuss/37182/my-recursive-solution-is-easy-and-clean https://leetcode.com/problems/flatten-binary-tree-to-linked...
Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 Hints: If you notice carefully in the flattened tree, each node's right child points to the next node of ...
packageleetcode/** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */// 解法一 非递归funcflatten(root*TreeNode){list,cur:=[]int{},&TreeNode{}preorder(root,&list)cur=rootfori:=1;i<len(list);i++{cur.Left=nil...
publicvoidflatten(TreeNoderoot){Stack<TreeNode>toVisit=newStack<>();TreeNodecur=root;TreeNodepre=null;while(cur!=null||!toVisit.isEmpty()){while(cur!=null){toVisit.push(cur);// 添加根节点cur=cur.right;// 递归添加右节点}cur=toVisit.peek();// 已经访问到最右的节点了// 在不存在左节...
一、原题114. Flatten Binary Tree to Linked List 二、前序遍历 + 展成单链 两步方式 首先通过前序遍历将节点存储到vector 中,然后将vector中的节点展成单链形式。 前序遍历(递归方式实现) /*** Definition for a binary tree node.* struct TreeNode {* int val;* TreeNode *left;* TreeNode *right...
TreeNode *left; TreeNode *right; TreeNode() {} TreeNode(int val) : val(val) {} TreeNode(int val, TreeNode *left, TreeNode *right) : val(val), left(left), right(right) {} }; class Solution { public: void flatten(TreeNode* root) { ...
LeetCode—108. Convert Sorted Array to Binary Search Tree 题目 https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/description/ 将一个递增数组转化为平衡二叉搜索树。平衡二叉搜索树首先是一个二叉搜索树,其次要求每一个节点的左右... ...
* Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: void flatten(TreeNode* root) { ...
If you notice carefully in the flattened tree, each node's right child points to the next node of a pre-order traversal. 原题链接:https://oj.leetcode.com/problems/flatten-binary-tree-to-linked-list/ 题目:给定二叉树,按前序位置展平成一个链表。
If you notice carefully in the flattened tree, each node's right child points to the next node of a pre-order trave 这道题要求把二叉树展开成链表,根据展开后形成的链表的顺序分析出是使用先序遍历,那么只要是数的遍历就有递归和非递归的两种方法来求解,这里我们也用两种方法来求解。首先来看递归版本的...