Flatten a Multilevel Doubly Linked List 参考资料: https://leetcode.com/problems/flatten-binary-tree-to-linked-list/ https://leetcode.com/problems/flatten-binary-tree-to-linked-list/discuss/37182/my-recursive-solution-is-easy-and-clean https://leetcode.com/problems/flatten-binary-tree-to-linked...
If you notice carefully in the flattened tree, each node's right child points to the next node of a pre-order traversal. Solution classSolution{private:TreeNode*getTail(TreeNode *node){if(node -> left ==NULL&& node -> right ==NULL) {returnnode; } TreeNode *leftTail = node -> left...
classSolution{public:voidflatten(TreeNode*root){if(root==nullptr){return;}autostk=stack<TreeNode*>();stk.push(root);TreeNode*prev=nullptr;while(!stk.empty()){TreeNode*curr=stk.top();stk.pop();if(prev!=nullptr){prev->left=nullptr;prev->right=curr;}TreeNode*left=curr->left,*right=cu...
publicvoidflatten(TreeNoderoot){Stack<TreeNode>toVisit=newStack<>();TreeNodecur=root;TreeNodepre=null;while(cur!=null||!toVisit.isEmpty()){while(cur!=null){toVisit.push(cur);// 添加根节点cur=cur.right;// 递归添加右节点}cur=toVisit.peek();// 已经访问到最右的节点了// 在不存在左节...
114. Flatten Binary Tree to Linked List # 题目 # Given a binary tree, flatten it to a linked list in-place. For example, given the following tree: 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 题目大意 # 给定一个
要求:Given a binary tree, flatten it to a linked list in-place.将二叉树转化为平坦序列的树。比如: 结题思路: 该题有个提示,转化后的树的序列正好是二叉树前序遍历所得到的序列,所以,该题第一个思路就是利用前序遍历的方式来做。 第二个思路:我们可以利用递归的思路,先对根节点进行处理,将root的左子...
* Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: void flatten(TreeNode* root) { ...
LeetCode—108. Convert Sorted Array to Binary Search Tree 题目 https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/description/ 将一个递增数组转化为平衡二叉搜索树。平衡二叉搜索树首先是一个二叉搜索树,其次要求每一个节点的左右... ...
* Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */classSolution{public:voidflatten(TreeNode*root){// Start typing your C/C++ solution below// DO NOT write int mai...
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { public void flatten(TreeNode root) { rightFlatten(root); ...