Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 click to show hints. Hints: If you notice carefully in the flattened tree, each node's right child points ...
Given therootof a binary tree, flatten the tree into a "linked list": The "linked list" should use the sameTreeNodeclass where therightchild pointer points to the next node in the list and theleftchild pointer is alwaysnull. The "linked list" should be in the same order as apre-orde...
publicvoidflatten(TreeNoderoot){Stack<TreeNode>toVisit=newStack<>();TreeNodecur=root;TreeNodepre=null;while(cur!=null||!toVisit.isEmpty()){while(cur!=null){toVisit.push(cur);// 添加根节点cur=cur.right;// 递归添加右节点}cur=toVisit.peek();// 已经访问到最右的节点了// 在不存在左节...
Flip Binary Tree To Match Preorder Traversal Given a binary tree with N nodes, each node has a different value from {1, ..., N}. A node in this binary tree can be flipped by swapping the left child and the right child of... ...
114. Flatten Binary Tree to Linked List # 题目 # Given a binary tree, flatten it to a linked list in-place. For example, given the following tree: 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 题目大意 # 给定一个
一、原题114. Flatten Binary Tree to Linked List 二、前序遍历 + 展成单链 两步方式 首先通过前序遍历将节点存储到vector 中,然后将vector中的节点展成单链形式。 前序遍历(递归方式实现) /*** Definition for a binary tree node.* struct TreeNode {* int val;* TreeNode *left;* TreeNode *right...
TreeNode *left; TreeNode *right; TreeNode() {} TreeNode(int val) : val(val) {} TreeNode(int val, TreeNode *left, TreeNode *right) : val(val), left(left), right(right) {} }; class Solution { public: void flatten(TreeNode* root) { ...
114. Flatten Binary Tree to Linked List 这道题自己一开始的做法是建立一个新链表然后再指向它,想到浪费空间看了题解 思路就是将左子树接在父节点的右子树上,将右子树接在左子树后,这样就是先序遍历的结果了 /** * Definition for a binary tree node....
[leetcode] 114. Flatten Binary Tree to Linked List Description Given a binary tree, flatten it to a linked list in-place. For example, given the following tree: 1 / \ 2 5 / \ \ 3 4 6 1. 2. 3. 4. 5. The flattened tree should look like:...
题目114. Flatten Binary Tree to Linked List Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / 2 5 / \ 3 4 6 The flattened tree should look like: 1 2 3 4 5 6 1,利用先序遍历...Leetcode 114. Flatten Binary Tree to Linked List Given a binary...