``` import java.util.ArrayList; import java.util.Arrays; import java.util.List; /** * Source : https://oj.leetcode.com/problems/flatten-binary-tree-to
展开后的单链表应该同样使用 TreeNode ,其中 right 子指针指向链表中下一个结点,而左子指针始终为 null 。 展开后的单链表应该与二叉树 先序遍历 顺序相同。 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/flatten-binary-tree-to-linked-list 著作权归领扣网络所有。商业转载请联系官方授权,非商...
Can you solve this real interview question? Flatten Binary Tree to Linked List - Given the root of a binary tree, flatten the tree into a "linked list": * The "linked list" should use the same TreeNode class where the right child pointer points to the
https://leetcode.com/problems/flatten-binary-tree-to-linked-list/ 题目: Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 思路: 递归处理每个结点,如果结点左孩...
[leetcode] 114. Flatten Binary Tree to Linked List Description Given a binary tree, flatten it to a linked list in-place. For example, given the following tree: 1 / \ 2 5 / \ \ 3 4 6 1. 2. 3. 4. 5. The flattened tree should look like:...
click to show hints. Anwser 1 : 代码语言:javascript 代码运行次数:0 运行 AI代码解释 /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} ...
请一键三连, 非常感谢LeetCode 力扣题解94. 二叉树的中序遍历94. Binary Tree Inorder Traversal帮你深度理解 二叉树 数据结构 递归算法 Morris遍历 迭代, 视频播放量 116、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 程序员写代码, 作者简介 Lee
Balanced Binary Tree 23 -- 6:11 App Leetcode-0114. Flatten Binary Tree to Linked List 89 -- 1:36 App Leetcode-0067. Add Binary 75 -- 3:26 App Leetcode-0102. Binary Tree Level Order Traversal 43 -- 4:43 App Leetcode-0095. Unique Binary Search Trees II 82 -- 6:19 ...
Identify the root of the binary tree using the last element of the postorder list. Find the root's position in the inorder list to determine the left and right subtrees. Recursively construct the left and right subtrees using the respective portions of the inorder and postorder lists. Return...
Given a binary tree, flatten it to a linked list in-place. For example,Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 ...