Find the nonzero elements in a 4-by-2-by-3 array. Specify two outputs,rowandcol, to return the row and column subscripts of the nonzero elements. When the input is a multidimensional array (N > 2),findreturnscolas a linear index over theN-1trailing dimensions ofX. X = zeros(4,2,3...
3 functions: [z isrise]=find_zeros(s); mn=loacal_minimums(s); mx=loacal_maximums(s); 팔로우 4.0 (1) 다운로드 수: 545 업데이트 날짜: 2011/11/1 라이선스 보기공유 MATLAB Online에서 열기 다운로드 ...
The zeros in the result indicate spots where both arrays have a value of zero. A = [5 7 0; 0 2 9; 5 0 0] A = 3×3 5 7 0 0 2 9 5 0 0 B = [6 6 0; 1 3 5; -1 0 0] B = 3×3 6 6 0 1 3 5 -1 0 0 A | B ans = 3x3 logical array 1 1 0 1 1 ...
This example shows how to use theCTLE Fitterapp to configure a CTLE block from SerDes Toolbox™ in theSerDes Designerapp or in Simulink®. You can use theCTLE Fitterapp to fit zeros, poles, and gains from a transfer function to create aGPZ Matrixand then export to your workspac...
在MATLAB中,可以使用函数find来查找结构化矩阵中特定索引的元素。find函数可以用于查找满足特定条件的元素的索引。 具体使用方法如下: 1. 创建一个结构化矩阵,例如: ```matlab...
MATLAB Online で開く How do I find the zeros locations in a array by using "for loop" and store in the new array matrix? Example: テーマコピー [1 2 3 0; 4 5 6 0; 7 8 0 9...] I need the output like テーマコピー [ 4 4 3] It's a zeros Location If zeros location...
Zero and Nonzero Elements in Matrix Find the nonzero elements in a 3-by-3 matrix. X = [1 0 2; 0 1 1; 0 0 4] X =3×31 0 2 0 1 1 0 0 4 k = find(X) k =5×11 5 7 8 9 Use the logicalnotoperator onXto locate the zeros. ...
The find() function in MATLAB is used to locate the indices of non-zero elements in an array or matrix. It is a versatile function that can be applied to vectors, matrices, and multidimensional arrays. The syntax of the find() function is flexible, accommodating different scenarios: indices...
计算和之和,结果放入序列,MATLAB代码如下 n = min( min(n1), min(n2) ):max( max(n1), max(n2) ); % y[n]的自变量范围 y1 = zeros(1,length(n)); y2 = y1; % y1,y2初始化成全0 y1( find( ( n >= min(n1) )&
MATLAB Online에서 열기 Ran in: 테마복사 a=rand(1,1000000); idx=find(diff([false diff(a)>0 false])); [lgtmax, j]=max(idx(2:2:end)-idx(1:2:end)); longestincreasedsubarray = a(idx(2*j-1)+(0:lgtmax-1)) longe...