(i) x^(2)+9x+18=x^(2)+6x+3x+18 {by splitting middle term] =x(x+6)+3(x+6)=)x+3(x+6) (ii) 6x^(2)+7x-3=6x^(2)+9x-2x-3 [by splitting middle term] (iii) 2x^(2) -7x -15=2x^(2) -10x+3x-15 [by splitting middle term] =2x(x-5)+3(x-5)=(2x+3)(x-5)
8(a) Factorise.(i)6x+93(2x-3) Final answer(a)(i)[1](ii)2ax+3a(ii)a(2x+3) Final answer[1](b)Use your answers to part (a) to factorise this expression.6x+9+2ax+3a(3+a)(2x-3) Final answer(b)[2] 相关知识点:
2x2+6x−5x−15=2x(x+3)−5(x+3)=(2x−5)(x+3)6. Final factorization: 2x3−3x2−17x+30=(x−2)(2x−5)(x+3) (ii) Factorize x3−6x2+11x−6 1. Identify the polynomial: The polynomial is x3−6x2+11x−6.2. Find the factors of the constant term (-6):...
百度试题 结果1 题目(b) Factorise fully 6x^3-27x^2+30x=3x(2x2-9x+10) [M1]=3x(2x-5)(x-2) 相关知识点: 试题来源: 解析 =3x(2x²-9x+10) [M1] = 3x(2x-5)(x-2) 反馈 收藏
3ab+62;a+b,b-c-|||-4-|||-axb;ax-b;x+1 52ax-ay;4bx-2by;2x--|||-y;a+26 6x2;a2+2ab+62;x+a+b;x--|||-a-b7(a+b)(a-b+x)8(y-1)(x1) 结果一 题目 II. Fill in the blanksFactorise:ab+b^2-ac-bc=()-() 4 Factorise:ax^2+ax-b-bx=()=() 5 Facto...
【题目】Factorise:-8xy+6xy2-2x3y. 相关知识点: 试题来源: 解析 【解析】-|||--2x3y(4x-3y+1) 结果一 题目 【题目】Factorise: -8x^4y+6x^3y^2-2x^3y. 答案 【解析】-2x^3y(4x-3y+1)相关推荐 1【题目】Factorise: -8x^4y+6x^3y^2-2x^3y....
百度试题 结果1 题目16 Factorise 6x^2+7x-20 .(3x-4)(2x+5) final answer..[2] 相关知识点: 试题来源: 解析 (3x-4)(2x+5) final answerB1 for (ax+b)(cx+d) where ac=6andad+bc=7 or bd=-20 反馈 收藏
11 (a) Factorise 6 a +3ay-4b-2by.6a-4b-3ay-2by=2(3a-2b)+y (3a-2b) [M1]=(3a-2b)(2+y)(3a-2b)(2+y)Answer (a)...(b) Faconsefuliy6x^3-27x^2+30x .=3x(2x^2-9x-10)[M1] =3x(2x-5)(x-2) 相关知识点: 试题来源: 解析 6a-4b+ 3ay-2by = 2...
II. Fill in the blanks4)m^2+m+()=()^225Factorise: 49a^2-36=6Fatose: 1/4y^2+y+1=7Factorise: (x+y)^2+6(x+y)+9==8Factorise: (x^2+2x)^2+2(x^2+2x)+1=9 Factorise: x^3-6x^2+9x=10 Factorise: x^2+2x+1-y^2= ...
8x+6x–2x+22y–2yCompleteyourdiagram Lettersfornumbers:a+b=10,whatcouldaandbbe?ifa=2,b=8whatisa+b?ifa=25,b=5whatisa+b?Letters,numbersandarea 6 2 b 5 Area?2x6=12 Area?5xb=5b Letters,numbersandarea 4 a 4 a Area?4x4=16Area?axa=a2 LettersandareayWhatisthearea yofthissquare?yxy=...