百度试题 结果1 题目Factorise: 2x^3-5x^2-19x+42 相关知识点: 试题来源: 解析 (x-2)(2x-7)(x+3)反馈 收藏
解答:提取公因式2,得到$2(x^2 - 2x + 1)$。然后利用完全平方公式,得到$2(x - 1)^2$。 将多项式$x^2 + 4x - 5$进行因式分解。 解答:利用十字相乘法,找到两个数-1和5,它们的和等于4,它们的积等于-5。然后将其与多项式的一次项和常数项组合,得到$(x - 1)(x + 5)$。...
2(b)(i)( 5 x - 4)(3 x + 2 )oe final answer 2(b)(i)4/5oeand-2/3oe 2(b)(i) B1 for (ax +b)(cx +d) where either ac = 15 and bd =-8 or ad + bc =-2 or 5x(3x+ 2)-4(3x+2) or 3x(5x-4)+ 2(5x-4) or correct factors seen and spoiled FT a fac...
The correct Answer is:(i) (√3x+2)(4x−√3) (ii) (x−√2)(7√2x+4) Let's factorise the given expressions step by step. (i) Factorise: 4√3x2+5x−2√3 Step 1: Identify the coefficients- The coefficients are a=4√3, b=5, and c=−2√3. Step 2: Multiply a and ...
(ii) Factorise 2x^4+5x^3-8x^2-8x+3 completely. 相关知识点: 试题来源: 解析 http://gallery.fbcontent.cn/latex?decode=false&latex=%24%24%5Cleft(x%5E%7B2%7D%2B3%20x-1%5Cright)(2%20x-3)(x%2B1)%24%24%25&fontSize=28 反馈 收藏 ...
11 (a) Factorise.5x-15..[1](b)Solve.4(3x-2)=28---[3](c)Simplify.(4a)/b*(3b^2)/(2a^2)[2](d) On the number line, show the inequality x≤3.4 3-i1034[1](e) Solve.7x3x+6---[2](f) Solve these simultaneous equations.x+y=5x-y=7r=y=...[2] 相关知识点: ...
such that a + b =5 and ab = 6. on solving this we obtain, a = 3 and b = 2 thus, the above expression can be written as: x 2 + 3x + 2x + 6 = x(x + 3) + 2(x + 3) = (x + 3)(x + 2) thus, x+3 and x+2 are the factors of the polynomial x 2 + 5x + ...
【题目】C. Questions that require solutionsFactorise the following:(1) x^2-5x+6(2) 4x^2-5(3) 4x^2+8x-1 ;(4) 3t^2-4t-1 ;(5)2y2-4y+1;(6) 2x^2-10xy+9y^2(7) -x^2-xy+y^2 ;(8) 2x^2y^2+4xy-3(9) -y^2x-4x^2y+2x^3(10) (x^3+x)^2-2x(x+1)-3 ...
1. Factor the following Polynomial: 2y^2 - 4y - 6 2. Factor the following Polynomial: 14y^2 - 9y - 1 Let f(x) = 3x^4 + x^3 + 4x^2 + 4x + 3 be a polynomial in Z_5x. Factorise f(x) as far as possible. Factorise the polynomial f(x) = 2x^3 +15x^2+3x-...
(a)f(11)= 2(11)^3- 17(11)² -58(11) + 33(subst.)Note: 2662- 2057- 638 + 33 earns M markORattempt at dividing 2x^3- 17x² - 58x+ 33by(x- 11).(b)2x²+5x2x²+5x- 3Note: The M1, A1marks above may possibly be obtained in (a) above.(x+3)(2x-1)(...