–7x -18 is a three-term polynomial. now we need to find two such numbers, whose product will give -18 and sum will give -7. thus, -9 x 2 = -18 -9 + 2 = -7 therefore, we can write the given polynomial as; x 2 –9x + 2x – 18 = x(x – 9) + 2(x – 9) = (...
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Factorize 12a^{5} + 8a. Factorize -x^2 + 4x - 3. Factorize: 7x^2 + 7x - 20 Factorize completely. 4a^4 b^2 - 8a^3b^2 + 12a^3b Factorize: 4 x^2 y + 8 x y. Factorize 4 x^3 - 5 x^2 + 7 x - 6. Factorize: 2x^2 + 10x ...
Factorise : 2x^2+7x+3. 03:34 The factors of 6x^2 + 5x - 6 are : 02:21 Factorise : 3x^2-x-4. 04:01 Factorise : x^3-2x^2-x+2. 06:59 Factorise : x^3-3x^2-9x-5. 04:01 Factorise : x^3+13x^2+32x+20. 07:13 Factorise : 2y^3+y^2-2y-1. 05:47Exams...
(a+b)2=a2+2ab+b2(a−b)2=a2−2ab+b2a2−b2=(a+b)(a−b) Answer and Explanation:1 We have to Factorise:25x2−9. We will apply the algebraic identities to factorize the given expression: $$\begin{align} 25x^2 - 9... ...
(3) x3+7x2+14x+8= (4) x3−3x2−10x+24= (5) x3+2x2−13x+10= 相关知识点: 试题来源: 解析 (1) (x−1)(x−2)(x−3) (2) (x+1)(x+2)(x−1) (3) (x+1)(x+2)(x+4) (4) (x+3)(x−2)(x−4) (5) (x+5)(x−1)(x−2) (1)略(2)略(3)...
(ii) 6x2+7x−3=6x2+9x−2x−3 [by splitting middle term] (iii) 2x2−7x−15=2x2−10x+3x−15 [by splitting middle term] =2x(x−5)+3(x−5)=(2x+3)(x−5) (iv) 84−2r−2r2=−2(r2+r−42) =−(r2+7r−6r−42) =−2[r(r+7)−69r...
Factorise: x^2 - 9x. Factorise 2 x^2 + 15 x - 27. Factorise: 7x^{5} + 7xy^{4} - 14x^{3}y^{2} Factorise: 2 m^3 - 5 m^2 + 9 m. Factorise: x^3 + 2x^2 + 3x + 6. Factorise: x^2 - 14x + 49. Factorise. 2w^{2}+11w-30 ...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
Factorise: x^3 + 2x^2 + 3x + 6. Factorise: 7x^{5} + 7xy^{4} - 14x^{3}y^{2} Factorise. 2\sqrt{3}=\sqrt{x^{2}+5x} Factorise : (1+ \frac{y^2+z^2-x^2}{2yz} ) / (1 - \frac{x^2+y^2-z^2}{2xy} ) ...