(ii) 6x2+7x−3=6x2+9x−2x−3 [by splitting middle term] (iii) 2x2−7x−15=2x2−10x+3x−15 [by splitting middle term] =2x(x−5)+3(x−5)=(2x+3)(x−5) (iv) 84−2r−2r2=−2(r2+r−42) =−(r2+7r−6r−42) =−2[r(r+7)−69r...
–7x -18 is a three-term polynomial. now we need to find two such numbers, whose product will give -18 and sum will give -7. thus, -9 x 2 = -18 -9 + 2 = -7 therefore, we can write the given polynomial as; x 2 –9x + 2x – 18 = x(x – 9) + 2(x – 9) = (...
结果1 结果2 题目【题目】Questions that require solutions(1)Factorise:3ax+4by+4ay+3bx .(2)Factorise:x^2-2xy-a^2+y^2 (3)Factorise:7x^2-3y+xy-21x .(4)Factorise:4a^2-4(ab+4)+b^2 .(5)Factorise:x^2-4xy+4y^2-2x+4y-3 .(6)Factorise:a^2-a^2b+ab^2-a+b-b^2. ...
58_expand-and-factorise Edexcel GCSE Mathematics (Linear) – 1MA0 ALGEBRA:EXPAND & FACTORISE Materials required for examination Items included with question papers Ruler graduated in centimetres and Nil millimetres, protractor, compasses,pen, HB pencil, eraser.Tracing paper may be used.Instructions...
Factorise : x^(3)+(1)/(x^(3))-2x-(2)/(x) 02:16 Factorise : 8a^(3)-b^(3)+1+6ab 01:42 Factorise : a^(6)+32a^(3)-64 03:20 Factorise : x^(3)+y^(3)-12xy+64 01:18 Factorise : (2x-y)^(3)-(x+y)^(3)+(2y-x)^(3) 03:42 Factorise : a^(3)+(1)/(a^...