(i) x^(2)+9x+18=x^(2)+6x+3x+18 {by splitting middle term] =x(x+6)+3(x+6)=)x+3(x+6) (ii) 6x^(2)+7x-3=6x^(2)+9x-2x-3 [by splitting middle term] (iii) 2x^(2) -7x -15=2x^(2) -10x+3x-15 [by splitting middle term] =2x(x-5)+3(x-5)=(2x+3)(x-5)
–7x -18 is a three-term polynomial. now we need to find two such numbers, whose product will give -18 and sum will give -7. thus, -9 x 2 = -18 -9 + 2 = -7 therefore, we can write the given polynomial as; x 2 –9x + 2x – 18 = x(x – 9) + 2(x – 9) = (...
百度试题 结果1 题目16 Factorise 6x^2+7x-20 .(3x-4)(2x+5) final answer..[2] 相关知识点: 试题来源: 解析 (3x-4)(2x+5) final answerB1 for (ax+b)(cx+d) where ac=6andad+bc=7 or bd=-20 反馈 收藏
Factorise : x^(3)+(1)/(x^(3))-2x-(2)/(x) 02:16 Factorise : 8a^(3)-b^(3)+1+6ab 01:42 Factorise : a^(6)+32a^(3)-64 03:20 Factorise : x^(3)+y^(3)-12xy+64 01:18 Factorise : (2x-y)^(3)-(x+y)^(3)+(2y-x)^(3) 03:42 Factorise : a^(3)+(1)/(a^...