百度试题 结果1 题目函数\(f(x)=\displaystyle \dfrac{1}{2}(2^x-2^{-x}) \) 是 \((\qquad)\). A. 奇函数 B. 偶函数 C. 指数函数 D. 非奇非偶函数 相关知识点: 试题来源: 解析 A 反馈 收藏
f(x)=2^\displaystyle {1\over x}在处的左极限存在,还是右极限存在? 相关知识点: 试题来源: 解析当x → -0时,(1 x)→ 0, 所以lim_(x → -0) 2^((1 x))=0, 所以左极限存在。当x → +0时,(1 x)→ +∞, 所以lim_(x → +0) 2^( (1 x))=+∞, 所以右极限不存在。
Answer to: Consider the function \displaystyle f(x)=\frac{1}{x+2}. Determine whether f(x) approaches \infty or -\infty as x approaches -2 from the...
Answer to: Given \displaystyle{ f(x) = x 2\sqrt{x}. } Prove that f is increasing for x 1. By signing up, you'll get thousands...
Evaluate the following integrals: (a) \displaystyle\int xe^{x^{2dx (b) \displaystyle\int(8t+5)^{13}dt (c) \displaystyle\int\frac{dx}{x\sqrt{lnx (d) \displaystyle\int_{-3}^{-1}\frac{y}{(y^{2}+5)^{2 Evaluate the integral \int_{0}^{x/...
考虑函数\(f\left( z \right)=\dfrac{{\rm e}^{{\rm i}z}}{(z^{2}+1)(z^{2}+9)}\), 在上半平面内有两个一阶极点\(z={\rm i},3{\rm i}\), 在这两点处的留数分别为\(\dfrac{\rm e^{-1}}{16\rm i}, \dfrac{\rm e^{-3}}{-48\rm i}\). 于是积分值为\(\dfr...
& \int_0^1 {x\left( {1 - \dfrac{{{x^2}}}{{1!}} + \dfrac{{{x^4}}}{{2!}} - \dfrac{{{x^6}}}{{3!}} + \cdots } \right)} {\rm{d}}x \\ ={}& \int_0^1 {x{{\rm{e}}^{ - {x^2}}} {\rm{d}}x = - \left. {\left( {\dfrac{1}{2}{{...
Answer to: Suppose that F(x) = \displaystyle \int_1^x f(t)\,dt, where f(t) = \displaystyle \int_1^{t^{1/3}} \dfrac{\sqrt{3 + u^5}}{u}\,du. Find...
Answer to: Find the indefinite integral: \int \frac {x}{x^2+1}dx By signing up, you'll get thousands of step-by-step solutions to your homework...
Evaluate the limit: lim x\rightarrow-\infty (5 + 2e^{2x})/(9- 3e^{3x}) . Evaluate the limit \lim_{x\rightarrow 0^+ } ((\tan x)( \ln x)) Evaluate the limit. \displaystyle \lim\limits_{x\to0} \frac{(\sqrt{1 + 4x} - \sqrt{1 - 5x})}{x} Ev...