#include <cstdio> #include <set> #include <string> #include <stack> #include <cmath> #include <climits> #include <map> #include <cstdlib> #include <iostream> #include <vector> #include <algorithm> #include <cstring> #include <bits/stdc++.h> usingnamespacestd; typedeflonglong(LL); ty...
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【每日leetcode】11.比特位计数 欢迎star /** * @author yitiaoIT */ class Solution { public int[] countBits(int n) { int count1...[] = new int[n+1]; count1[0]=0; for (int i = 0; i <= n; i++) { if(i%2==0)...{ count1[i]=count1[i/2]; } else { count1[i]...
STL提供的函数upper_bound, lower_bound能够快速找到这样的j的范围,因为set有序范围内的一定满足上面的条件. set使用红黑树来实现,因此上面的操作时间复杂度O(logN). 所以总的时间复杂度为O(NlogN). **/intLeetCode::countRangeSum(vector<int>& nums,intlower,intupper){ multiset<longlong>sums;//注意使用l...
今天在leetcode写了一个题 两数之和 这是AC代码 class Solution { public: vector<int> twoSum(vector<int>& nums, int target) { vector<int> a; map<int,int> p; for (int i=0; ... C++黑科技 i++ 赋值 c代码 转载 mb5fe191195f1f1 ...
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My Solutions to Leetcode problems. All solutions support C++ language, some support Java and Python. Multiple solutions will be given by most problems. Enjoy:) 我的Leetcode解答。所有的问题都支持C++语言,一部分问题支持Java语言。近乎所有问题都会提供多个算