Java [Leetcode 338]Counting Bits 题目描述: Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example:For num = 5 you should return [0,1,1,2,1,2]. ...
java实现的源码 publicclassSolution {publicint[] countBits(intnum) {int[] ans =newint[num + 1];for(inti = 1; i <= num; ++i) ans[i]= ans[i & (i - 1)] + 1;returnans; } } 源码来源:https://leetcode-cn.com/problems/counting-bits/solution/bi-te-wei-ji-shu-by-leetcode/ ...
LeetCode Top 100 Liked Questions 338. Counting Bits (Java版; Medium) 题目描述 Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example 1: Input: 2 Output: ...
leetcode 338. Counting Bits 位计算 + 统计二进制1的数量 Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1’s in their binary representation and return them as an array. Example: For num = 5 you should return [0,1,1,...
leetcode 338 Counting Bits 题目大意: 给定一个非负整数num,要求你计算 0<=i<=num范围中,每个i的二进制表示中,有几个1; 例如,给定num=5,那么在0<=i<=num的范围汇中的数为{0,1,2,3,4,5},那么他们对应的二进制表示中,各自含有的1的个数为{0,1,1,2,1,2}。 两种解题思路: 第一种解题思路,写...
Counting Bits public int[] countBits(int num Leetcode:338.比特位计数 给定一个非负整数 num。对于 0≤ i≤ num 范围中的每个数字i ,计算其二进制数中的 1 的数目并将它们作为数组返回。 示例 1: 示例 2: 进阶: 给出时间复杂度为O...函数(如 C++ 中的 __builtin_popcount)来执行此操作。 解题...
LeetCode 338 Counting Bits 原题链接: Counting Bits 题目大意: 输入一个数字num,输出一个数组,表示从0到num的所有数字的二进制形式中,1的个数。 解题思路: 找规律。 0: [0] 1: [0,1+a[0]] 2: [0,1+a[0],1+a[0]] 3: [0,1+a[0],1+a[0],1+a[1]] 4: [0,1+a[0],1+a[0]...
原题链接在这里:https://leetcode.com/problems/counting-bits/ 题目: Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. ...
https://leetcode.com/problems/counting-bits/ https://leetcode.com/discuss/92796/four-lines-c-time-o-n-space-o-1 https://leetcode.com/discuss/92694/my-408-ms-c-solution-using-bitset https://leetcode.com/discuss/92698/my-448ms-c-easy-solution-o-n-time-and-o-n-space ...
LeetCode "Counting Bits" Neat DP problem to go. frommathimport*classSolution(object):defcountBits(self, num): ret=[0]foriinrange(1, num + 1):ifi & 1:#oddret += [ret[-1] + 1]else: prev= i - 1trailing1s= (i | prev) -i...