public int[] countBits(int num) { int[] arr = new int[num + 1]; arr[0] = 0; if (num <= 0) { return arr; } arr[1] = 1; //当前执行到的数 int index = 1; //当前到达的平方数 int powNum = 0; //上次到达的数 int powSum = (int) Mat
java实现的源码 publicclassSolution {publicint[] countBits(intnum) {int[] ans =newint[num + 1];for(inti = 1; i <= num; ++i) ans[i]= ans[i & (i - 1)] + 1;returnans; } } 源码来源:https://leetcode-cn.com/problems/counting-bits/solution/bi-te-wei-ji-shu-by-leetcode/ ...
leetcode 338. Counting Bits 位计算 + 统计二进制1的数量 Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1’s in their binary representation and return them as an array. Example: For num = 5 you should return [0,1,1,...
LeetCode Top 100 Liked Questions 338. Counting Bits (Java版; Medium) 题目描述 Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example 1: Input: 2 Output: ...
publicint[] countBits(intnum){ int[] res =newint[num +1]; intpow =1, k =1; res[0] =0; while(k <= num){ if(k == pow){ pow *=2; res[k++] =1; }else{ res[k] = res[pow /2] + res[k - pow /2]; k++; ...
leetcode 338. Counting Bits 统计数字的二进制表示的中的 1 的个数 自己写的 思路 9 = ret[8] + ret[9-8] 12 = ret[8]+ret[12-8] i = ret[ 小于i的2的最大幂次 j ] +ret[ i-j ] 代码 看到别人的代码 才知道什么叫做 excellent idea 参考 338. Counting Bits 数字的二进制中1的个数...
LeetCode 338. Counting Bits 简介:给定一个非负整数 num。对于 0 ≤ i ≤ num 范围中的每个数字 i ,计算其二进制数中的 1 的数目并将它们作为数组返回。 Description Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in ...
LeetCode-338-比特位计数 httpsc++网络安全编程算法 题目来自于力扣https://leetcode-cn.com/problems/counting-bits benym 2022/07/14 1560 LeetCode 训练场:338. 比特位计数 c++编程算法 1. 题目 338. 比特位计数 2. 描述 给定一个非负整数 num。对于 0 ≤ i ≤ num 范围中的每个数字 i ,计算其二进...
publicint[]countBits(intnum){int[]res=newint[num+1];for(inti=0;i<res.length;i++)res[i]=res[i>>>1]+(i&1);returnres;}
LeetCode 338. Counting Bits 创新互联公司是一家专注于网站建设、成都做网站与策划设计,汉阳网站建设哪家好?创新互联公司做网站,专注于网站建设10多年,网设计领域的专业建站公司;建站业务涵盖:汉阳等地区。汉阳做网站价格咨询:18982081108 Given a non negative integer number num. For every numbers i in the range ...