代码: #Definition for a binary tree node#class TreeNode:#def __init__(self, x):#self.val = x#self.left = None#self.right = NoneclassSolution:#@param root, a tree node#@return a list of integersdefiterative_inorder(self, root, list): stack=[]whilerootorstack:ifroot: stack.append...
链接:https://leetcode-cn.com/problems/binary-tree-inorder-traversal python # 0094.二叉树中序遍历 # 递归 & 迭代 class Solution: def inOrderRecur(self,head: TreeNode) -> int: """ 递归遍历,LNR, 左根右 :param head: :return: """ def traversal(head): # 递归终止条件 ifhead== None: ...
代码 python defpostorderTraversal(root):""" :type root: TreeNode :rtype: List[int] """rs=[]defdfs(node):ifnode:dfs(node.left)dfs(node.right)rs.append(node.val)dfs(root)returnrsdefpostorderTraversalV2(root):defdfs(node):ifnotnode:return[]returndfs(node.left)+dfs(node.right)+[node....
树定义 # tree definitionclassTree(object):def__init__(self,root=None):self.root=root# node in-order traversal(LDR)deftraversal(self):traversal(self.root)# insert nodedefinsert(self,value):self.root=insert(self.root,value)# delete nodedefdelete(self,value):self.root=delete(self.root,value) ...
同Construct Binary Tree from Inorder and Postorder Traversal(Python版) # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def buildTree(self, pre...
094.binary-tree-inorder-traversal Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree [1,null,2,3], 1 \ 2 / 3 return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively?
中序遍历(Inorder Traversal) 从根节点开始,首先按照中序遍历的方式访问左子树,然后访问根节点,最后访问右子树。中序遍历通常用于访问二叉搜索树中的节点,以升序或降序访问节点值。 访问顺序:左子树 -> 根节点 -> 右子树 Leetcode 94. 二叉树的中遍历【简单】 ...
vector<int> inorderTraversal(TreeNode *root) { vector<int> res; stack<TreeNode* > s; TreeNode* current=root; while(!s.empty()||current!=NULL) { if(current!=NULL) { s.push(current);// 根先进,在继续左孩子,直到为空 current=current->left; ...
[-1]whilestack: node = stack.pop()ifnode.right: node = node.rightwhilenode: stack.append(node) node = node.left# the only difference compare to an inorder traversal iteration# this problem disallowed equal values so it's <= not <ifstack:ifstack[-1].val <= last_node.val:return...
# tree definitionclassTree(object):def__init__(self,root=None):self.root=root # nodein-ordertraversal(LDR)deftraversal(self):traversal(self.root)# insert node definsert(self,value):self.root=insert(self.root,value)#deletenode defdelete(self,value):self.root=delete(self.root,value) ...