Given a binary search tree, print the elements in-order iteratively without using recursion. Note: Before you attempt this problem, you might want to try coding a pre-order traversal iterative solution first, b
这个遍历方式也是LeetCode中 Binary Tree Inorder Traversal 一题的解法之一。 附题目,Binary Tree Inorder Traversal Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. Note:Recursive solution is trivial,...
public: vector<int> inorderTraversal(TreeNode* root) { vector<int> res; inorder(res,root); return res; } private: void inorder(vector<int>& res,TreeNode* root){ if(root==NULL) return; inorder(res,root->left); res.push_back(root->val); inorder(res,root->right); } }; 1. 2...
public List<Integer> inorderTraversal3(TreeNode root) { List<Integer> ans = new ArrayList<>(); TreeNode cur = root; while (cur != null) { //情况 1 if (cur.left == null) { ans.add(cur.val); cur = cur.right; } else { //找左子树最右边的节点 TreeNode pre = cur.left; whi...
题目描述英文版描述Given the root of a binary tree, return the inorder traversal of its nodes' values. Example 1: Input: root = [1,null,2,3] Output: [1,3,2] Example 2: Input: root = [] Output: []…
Using these new definitions, the leaf nodes in binary tree (a) are nodes 6 and 8; the internal nodes are nodes 1, 2, 3, 4, 5, and 7.Unfortunately, the .NET Framework does not contain a binary tree class, so in order to better understand binary trees, let's take a moment to ...
Unfortunately, the .NET Framework does not contain a binary tree class, so in order to better understand binary trees, let's take a moment to create our own binary tree class. The First Step: Creating a Base Node Class The first step in designing our binary tree class is to create a ...
For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line. ...
Similar to pre-order and in-order traversal, accessing the binary tree in the order of left child->right child->root node is called post-order traversal. The first visited node in the post-order traversal is与先序、中序遍历类似,以左子->右子->根节点的顺序来访问二叉树称为后序遍历。后序...
classSolution{publicList<Integer>inorderTraversal(TreeNoderoot){if(root==null)returnnewArrayList<Integer>();TreeNodecurrentNode=root;Stack<TreeNode>tracker=newStack<>();List<Integer>result=newArrayList<>();while(currentNode!=null||!tracker.isEmpty()){while(currentNode!=null){tracker.push(currentNo...