Given a binary search tree, print the elements in-order iteratively without using recursion.Note:Before you attempt this problem, you might want to try coding a pre-order traversal iterative solution first, because it is easier. On the other hand, coding a post-order iterative version is a ...
这个遍历方式也是LeetCode中 Binary Tree Inorder Traversal 一题的解法之一。 附题目,Binary Tree Inorder Traversal Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. Note:Recursive solution is trivial,...
public: vector<int> inorderTraversal(TreeNode* root) { vector<int> res; inorder(res,root); return res; } private: void inorder(vector<int>& res,TreeNode* root){ if(root==NULL) return; inorder(res,root->left); res.push_back(root->val); inorder(res,root->right); } }; 1. 2...
publicList<Integer>inorderTraversal(TreeNoderoot){List<Integer>ans=newArrayList<>();Stack<TreeNode>stack=newStack<>();TreeNodecur=root;while(cur!=null||!stack.isEmpty()){//节点不为空一直压栈while(cur!=null){stack.push(cur);cur=cur.left;//考虑左子树}//节点为空,就出栈cur=stack.pop()...
Given abinary tree, return theinordertraversal of its nodes' values. 知识点: Recursion Iteration Threaded binary tree 二刷: 要求的iteration: 最初做法: class Solution: def inorderTraversal(self, root: TreeNode) -> List[int]: if not root: return [] ...
Unfortunately, the .NET Framework does not contain a binary tree class, so in order to better understand binary trees, let's take a moment to create our own binary tree class. The First Step: Creating a Base Node Class The first step in designing our binary tree class is to create a ...
For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line. ...
Unfortunately, the .NET Framework does not contain a binary tree class, so in order to better understand binary trees, let's take a moment to create our own binary tree class. The First Step: Creating a Base Node Class The first step in designing our binary tree class is to create a ...
classSolution{publicList<Integer>inorderTraversal(TreeNoderoot){if(root==null)returnnewArrayList<Integer>();TreeNodecurrentNode=root;Stack<TreeNode>tracker=newStack<>();List<Integer>result=newArrayList<>();while(currentNode!=null||!tracker.isEmpty()){while(currentNode!=null){tracker.push(currentNo...
Integer>result=newArrayList<Integer>();if(root==null)returnresult;inorderTraversal(root,result);returnresult;}privatevoidinorderTraversal(TreeNode root,ArrayList<Integer>result){if(root.left!=null)inorderTraversal(root.left,result);result.add(root.val);if(root.right!=null)inorderTraversal(root....