这个遍历方式也是LeetCode中 Binary Tree Inorder Traversal 一题的解法之一。 附题目,Binary Tree Inorder Traversal Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. Note:Recursive solution is trivial,...
Given a binary search tree, print the elements in-order iteratively without using recursion.Note:Before you attempt this problem, you might want to try coding a pre-order traversal iterative solution first, because it is easier. On the other hand, coding a post-order iterative version is a ...
publicList<Integer>inorderTraversal3(TreeNoderoot){List<Integer>ans=newArrayList<>();TreeNodecur=root;while(cur!=null){//情况 1if(cur.left==null){ans.add(cur.val);cur=cur.right;}else{//找左子树最右边的节点TreeNodepre=cur.left;while(pre.right!=null&&pre.right!=cur){pre=pre.right;}...
Given the root of a binary tree, return the inorder traversal of its nodes' values. Example 1: Input: root = [1,null,2,3] Output: [1,3,2] Example 2: Input: root = [] Output: [] Example 3: Input: root = [1] Output: [1] Constraints: The number of nodes in the tree is...
Preorder traversal starts printing from the root node and then goes into the left and right subtrees, respectively, while postorder traversal visits the root node in the end. #include<iostream>#include<vector>using std::cout;using std::endl;using std::string;using std::vector;structTreeNode{...
Given a binary tree, return the inorder traversal of its nodes' values. 主要思路: 1.递归 保持左根右的顺序即可 代码: definorderTraversal(self,root):""" :type root: TreeNode :rtype: List[int] """ifroot==None:return[]left=self.inorderTraversal(root.left)right=self.inorderTraversal(root...
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: /*递归版 vector<int> inorderTraversal(TreeNode *root) { vector<int> res; solve(root,res); return res; } void solve(TreeNode *root,vector<int> &res) ...
*/voidtraversal(structTreeNode*root,int*countPointer,int*res){if(!root)return;traversal(root->left,countPointer,res);res[(*countPointer)++]=root->val;traversal(root->right,countPointer,res);}int*inorderTraversal(structTreeNode*root,int*returnSize){int*res=malloc(sizeof(int)*110);intcount=...
Preorder traversal Inorder traversal Postorder traversalEssentially, all three traversals work in roughly the same manner. They start at the root and visit that node and its children. The difference among these three traversal methods is the order with which they visit the node itself versus ...
Preorder traversal Inorder traversal Postorder traversalEssentially, all three traversals work in roughly the same manner. They start at the root and visit that node and its children. The difference among these three traversal methods is the order with which they visit the node itself versus ...