self.inorder(root.right, list)definorderTraversal(self, root): list=[] self.iterative_inorder(root, list)returnlist
链接:https://leetcode-cn.com/problems/binary-tree-inorder-traversal python # 0094.二叉树中序遍历 # 递归 & 迭代 class Solution: def inOrderRecur(self,head: TreeNode) -> int: """ 递归遍历,LNR, 左根右 :param head: :return: """ def traversal(head): # 递归终止条件 ifhead== None: ...
class Solution(object): def inorderTraversal(self, root): """ :type root: TreeNode :rtype: List[int] """ if not root: return [] else: return self.inorderTraversal(root.left) + [root.val] + self.inorderTraversal(root.right) 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 迭代 和前...
这两个要求可以用同一种逻辑实现,即节点A的值大于等于节点B的值,则返回False。 因此我们使用中序遍历(In-Order Traversal),先左后中,先中后右,并确以该顺序遍历的值不断增大。一旦没有增大,立刻返回False,不然继续以此顺序遍历至None节点返回。 对于一个节点来说,其左子树先于它给cur_max赋值,它先于右子树给...
Tree and its inorder traversal using python. Binary treeis the tree where one node can have only two children and cannot have more than two. Traversal means visiting all the nodes of the Binary tree. There are three types of traversal. ...
leetcode 94.二叉树的中序遍历(binary tree inorder traversal)C语言 1.description 2.solution 2.1 递归 2.2 迭代 1.description https://leetcode-cn.com/problems/binary-tree-inorder-traversal/ 给定一个二叉树,返回它的中序 遍历。 示例: 输入: [...猜...
094.binary-tree-inorder-traversal Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree [1,null,2,3], 1 \ 2 / 3 return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively?
(Tree, element) return Tree class Solution(object): def postorderTraversal(self, root): if not root: return [] res = [] stack = [[root,0]] while stack: node = stack[-1] stack.pop() if node[1]== 0 : current = node[0] stack.append([current,1]) if current.right: stack....
Given a binary tree, return theinordertraversal of its nodes' values. 示例: 代码语言:javascript 代码运行次数:0 AI代码解释 输入:[1,null,2,3]1\2/3输出:[1,3,2] 进阶:递归算法很简单,你可以通过迭代算法完成吗? Follow up:Recursive solution is trivial, could you do it iteratively?
题目: 给定一个二叉树,返回它的 中序 遍历。 Given a binary tree, return the inorder traversal of its nodes' values.