对于第一种解法,可以适当再优化下,大体逻辑一致,不过在使用StringBuilder存储字符串的时候,使用的append方法,所以最后需要将其反转,才是最终我们需要的结果。 public String addBinary2(String a, String b) { StringBuilder sb = new StringBuilder();inti = a.length() -1;intj = b.length() -1;intcarry =...
}publicstaticString addBinary(String a, String b) {if(a==null||a.equals("0"))returnb;if(b==null||b.equals("0"))returna;intlen1=a.length();intlen2=b.length();intlen;if(len1<len2) len=len1;elselen=len2;inti;char[] ca=a.toCharArray();char[] cb=b.toCharArray(); String ...
题目地址:https://leetcode.com/problems/add-binary/description/ 题目描述 Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" 1...
public String addBinary(String a, String b) { int i = a.length() - 1, j = b.length() - 1, carry = 0; StringBuilder sb = new StringBuilder(); while(i >=0 || j >=0){ int m = i >= 0 ? a.charAt(i) - '0' : 0; int n = j >= 0 ? b.charAt(j) - '0' : 0...
要完成的函数: string addBinary(string a, string b) 说明: 1、本题实现二进制的加法,无论有多少位二进制均可以处理。不采用常规的二进制转十进制,十进制相加,结果再转回二进制的做法,是因为这样子很麻烦,而且对于超过int表示范围的数,这种常 chenjx85 2018/05/21 5900 LeetCode——Add Binary httpsjava...
067 Add Binary 二进制求和 给定两个二进制字符串,返回他们的和(用二进制表示)。 案例: a = "11" b = "1" 返回"100" 。 详见:https://leetcode.com/problems/add-binary/description/ Java实现: class Solution { public String addBinary(String a, String b) {...
[Leetcode] Expression Add Operators 添加运算符 Expression Add Operators Given a string that contains only digits 0-9 and a target value, return all possibilities to add binary operators (not unary)+,-, or*between the digits so they evaluate to the target value....
* <h4><a href="https://leetcode.com/problems/merge-two-binary-trees/description/">Merge Two Binary Trees</a></h4> * Merges two binary trees by adding the values of nodes that overlap.</h4> * </h4> * If two nodes overlap, their values are added together, and the result is assig...
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[LeetCode] Add One Row to Tree 二叉树中增加一行 简介:Given the root of a binary tree, then value v and depth d, you need to add a row of nodes with value v at the given depth d. Given the root of a binary tree, then valuev and depth d, you need to add a row of nodes ...