【Leetcode】Add Binary 题目: Given two binary strings, return their sum (also a binary string). For example, a ="11" b ="1" Return"100". 解题思路1:判断当前字符所表示的数字,产生输出和进位。缺点:程序比较复杂。 代码1: class Solution { public: string addBinary(string a, string b) { ...
publicclassSolution {publicString addBinary(String a, String b) {if(a.equals("") && b.equals(""))return"0";if(a ==null|| a.equals("") || a.equals("0"))returnb;if(b ==null|| b.equals("") || b.equals("0"))returna;char[] a1 =a.toCharArray();char[] b1 =b.toCharArr...
usestd::iter; implSolution{ pubfnadd_binary(a:String,b:String)->String{ //进位,初始为0 letmutcarry=0; //收集a和b按位加的结果 letmutresult=a //返回底层的字节切片 .as_bytes() //转换成迭代器 .iter() //提前反向迭代(后面会加上无限的'0',所以不能后面同时反向) .rev() //在a后面...
https://leetcode.com/problems/add-binary/ 知道二进制加法原理即可,这里只需要知道进位是除数,余数是结果就行。最后不要忽略reg里面的值 class Solution(object): def addBinary(self, a, b): """ :type a: str :type b: str :rtype: str """ if not a: return b elif not b: return a tmp_...
classSolution:defaddBinary(self,a:str,b:str)->str:sumInt=int(a,2)+int(b,2)sumBin=bin(sumInt)#string starts with '0b'returnsumBin[2:]# equally, but more precise# return bin( int(a, 2) + int(b, ) )[2:]# return '{:b}'.format(int(a, 2) + int(b, 2))# return f"...
题目地址:https://leetcode.com/problems/add-binary/description/ 题目描述 Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: ...
Leetcode - Add Binary Paste_Image.png My code: public class Solution { public String addBinary(String a, String b) { if (a == null || a.length() == 0 || b == null || b.length() == 0) return null; int len = Math.max(a.length(), b.length()) + 1;...
Add Binary https://leetcode.com/problems/add-binary/description/ 主要是全加器的公式: s = abc c = (a^b)&c | (a&b) 其他的没什么 就去一下零处理 以及颠倒一下列表 classSolution(object):defaddBinary(self,a,b):""" :type a: str...
Leetcode-Add Binary Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 二进制相加,字符串输入,字符串输出 public class Solution { public String addBinary(String a, String b) { ...
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