题目地址:https://leetcode.com/problems/add-binary/description/ 题目描述 Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input:a ="11", b ="1"Output:"100" Example 2: Input:a ="...
class Solution: # @param a, a string # @param b, a string # @return a string def addBinary(self, a, b): length = max(len(a),len(b)) + 1 sum = ['0' for i in range(length)] if len(a) <= len(b): a = '0' * ( len(b) - len(a) ) + a if len(a) > len(b...
classSolution:defaddBinary(self,a:str,b:str)->str:sumInt=int(a,2)+int(b,2)sumBin=bin(sumInt)#string starts with '0b'returnsumBin[2:]# equally, but more precise# return bin( int(a, 2) + int(b, ) )[2:]# return '{:b}'.format(int(a, 2) + int(b, 2))# return f"{...
日期 题目地址:https://leetcode.com/problems/add-binary/description/ 题目描述 Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1...
class Solution(object): def addBinary(self, a, b): """ :type a: str :type b: str :rtype: str """ result = [] val = 0 carry = 0 lenA = len(a) lenB = len(b) if lenA < lenB: # 注意坑:确保A比B长, 所以值长度也要交换 a, b = b, a lenA, lenB = lenB, lenA for...
LeetCode 0067 - Add Binary的解题思路是什么? 如何用Python实现LeetCode 0067 - Add Binary? LeetCode 0067 - Add Binary的时间复杂度是多少? Add Binary Desicription Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". Solution 代...
类似题目:LeetCode 67 - Add Binary | 二进制求和 (Rust) 时间复杂度:O(|l1| + |l2|) 需要遍历 l1 中的全部 O(|l1|) 个结点 需要遍历 l2 中的全部 O(|l2|) 个结点 空间复杂度:O(1) 需要为结果链表中的全部 O(max(|l1|, |l2|)) 个结点分配空间 (理论上可以复用已有的结点,这样就只需要定...
[LeetCode-67]-Add Binary(二进制相加) 题目相关 【题目解读】 【原题描述】 Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1"...
Python实现: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 class Solution: def addBinary(self, a, b): """ :type a: str :type b: str :rtype: str """ ans = '' alen = len(a); blen = len(b) if alen < blen: # 如果两字符串不相等,则较短的字符串前面补0到与较长的字符串...
Breadcrumbs leetcode-solutions /python / 0724-find-pivot-index.py Latest commit mainframer Update file names 53c9d2a· Dec 27, 2022 HistoryHistory File metadata and controls Code Blame 11 lines (10 loc) · 315 Bytes Raw class Solution: def pivotIndex(self, nums: List...