classSolution {public:stringaddBinary(stringa,stringb) {//首先把字符串放到数组中vector<int> A;//用于存放字符串avector<int> B;//用于存放字符串bstringresult ;//定义返回字符串intcounter =0;//进位器if(a.size() >= b.size())//比较两个字符串大小,及比较两个数的位长,长的放在A中,短的放...
b[n--] -'0':0;intsum = p + q +carry; res= to_string(sum %2) +res; carry= sum /2; }returncarry ==1?"1"+res : res; } }; Github 同步地址: https://github.com/grandyang/leetcode/issues/67 类似题目: Add Binary Multiply Strings Plus One Linked List Plus One Add Two Number...
Given two binary stringsaandb, returntheir sum as a binary string. Example 1: Input:a = "11", b = "1"Output:"100" Example 2: Input:a = "1010", b = "1011"Output:"10101" Constraints: 1 <= a.length, b.length <= 104 aandbconsist only of'0'or'1'characters. Each string does...
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" 1. 2. Example 2: Input: a = "1010", b = "1011" Output: "10101" 1. 2. 题目...
LeetCode Add Binary Given two binary strings, return their sum (also a binary string). For example, a ="11" b ="1" Return"100". 题意:二进制的加法。 思路:跟大数加法差点儿相同。 classSolution{public:stringaddBinary(string a,string b){stack<int>s;intna=a.size()-1;intnb=b.size()...
usestd::iter; implSolution{ pubfnadd_binary(a:String,b:String)->String{ //进位,初始为0 letmutcarry=0; //收集a和b按位加的结果 letmutresult=a //返回底层的字节切片 .as_bytes() //转换成迭代器 .iter() //提前反向迭代(后面会加上无限的'0',所以不能后面同时反向) .rev() //在a后面...
Leetcode - Add Binary Paste_Image.png My code: public class Solution { public String addBinary(String a, String b) { if (a == null || a.length() == 0 || b == null || b.length() == 0) return null; int len = Math.max(a.length(), b.length()) + 1;...
Add binary 通过String模拟实现二进制的加法。和其他很多事情一样,计算加法看起来简单。至少对于人脑来说,可以说是最基本的逻辑操作。要通过编程实现,对于小白的我来说,仍然需要一番努力。 Given two binary strings, return their sum (also a binary string)....
LeetCode 0067 - Add Binary的解题思路是什么? 如何用Python实现LeetCode 0067 - Add Binary? LeetCode 0067 - Add Binary的时间复杂度是多少? Add Binary Desicription Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". Solution 代...
Giventwobinary strings,returntheirsum(alsoabinarystring). For example,a="11"b ="1"Return"100". 分析 我一开始写了这个算法,虽然实现了功能,不过不符合题目的用意。 intctoi(char c) {return(int)c -48; }intpow2(intn) {intsum =1;while((n--) >0) ...