∫ex2+lnxdx View Solution Evaluate: (i)∫(sin(logx)xdx(ii)∫emtan(−1)x1+x2dx View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium
What is int0^a (f(a -x))/(f(x) +f(a-x))dx equal to ? 03:10 What is lim(x to -1) (x^3 + x^2)/(x^2 + 3x + 2) equal to ? 01:37 If int0^a{f(x)+f(-x)}dx=int-a^aphi(x)dxthen phi(x)=. 01:34 What is the area bounded by y= sqrt(16-x^2)y gt...
Use integration by parts to find the following integral: {eq}\displaystyle \int \ln(x^2+1) \ dx {/eq} Integration by Parts The process of integration by parts is applied into integrals where the integrand is a product of two functions. in integration by parts, t...
Answer to: Use integration by parts to evaluate the following integral. \int x^2 ln(x) dx By signing up, you'll get thousands of step-by-step...
(1)1→e∫[(ln² x)/ x] dx=(1/3)(lnx)3|1→e=(1/3)(1-0)=1/3(2)0→1∫cos(ωt+φ)dt=(1/ω)sin(ωt+φ)|0→1=(1/ω)sin(ω+φ)(3)0→4∫[1/(1+√x)] dx,令t=√x,则dx=dt²=2tdt,[1/(1+√x)] dx=[2t /(1+t)] dt,条件:x=0...
lv$$ | \ln x \cdot x^{2}d_{v} $$ $$ = \int \ln xd \frac{1}{3}x^{3} \\ = \frac{1}{3}x^{3}/nx-| \frac{1}{3}x^{3}d \ln x \\ = \frac{1}{3}x^{3}\ln x- \frac{1}{3}\int x^{2}dx \\ = \frac{1}{3}x^{3}/nx- \frac{1}{9}x^{3}+c $...
int_ (1)^(e^(2))(dx)/(x(1+log x)^ (2))= View Solution int_(c)^( If )x ln(1+ (1)/(x))(:dx=p(x)backslash ln(1+(1)/(x))+(1)/ (2)x-(1)/(2)ln(1+x)+c View Solution The value of ∫1−1(logx+√1+x2)x+log(x+√1+x2)f(x)dx−∫1−1log(x√...
Evaluate the integral {eq}\int x\ln(x^2) \,dx {/eq} Integration By Parts: The derivative of the log function is a rational function. So by using integration by parts, we can convert the integral into a rational integral. We integrate the rational function by using the power rule. ...
Answer to: Evaluate the integral: \int (x^{\frac{3}{2}} + \ln 2x) dx By signing up, you'll get thousands of step-by-step solutions to your...
\int {ln^3x\over x^2}dx=\int ln^3xd(-{1\over x})=-{ln^3x\over x}+\int {3ln^2x\over x^2}dx=-{ln^3x\over x}+3\int {ln^2xd(-{1\over x})=-{ln^3x\over x}-3{ln^2x\over x}+6\int {lnx\over x^2}dx=-{ln^3x\over x}-3{ln^2x\over x}+6\int {lnx}d(...